So all you need to do if find the min of the function:
f(x)=0.04x^3-4x^2-176x
f'(x)=0.12x^2-8x-176
The only zero for this is x=84.105 <---first
Plug this into f(x) to get f(84.105)=-19300 <---second
Answer:
Step-by-step explanation:
<u>Given</u>
<u>Cross multiply and solve for x:</u>
Answer:
a=11
Step-by-step explanation:
a=m2 +2
a= (-3)2+2
a=9+2
a=11
