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Art [367]
4 years ago
12

A restaurant offers a "Create Your Own Pizza" menu option. There are 3 types of meat, 6 types of vegetables, and 3 kinds of chee

se. Customers may choose one meat, one vegetable, and one cheese. You decide to have the chef choose the toppings randomly. What is the probability that the chef will make a pizza with chicken, banana peppers, and ricotta cheese?
Mathematics
1 answer:
zheka24 [161]4 years ago
6 0
Multiply 3 times 6 times 3 to get the total number of choices.
Since there can only be one meat, one vegetable, and one cheese, the chances are 1/54.
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<h2>Step-by-step explanation:</h2>

We know that the general equation of a quadratic equation in terms of a variable x is given by:

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A)

y(y + 4) - y = 6

On simplifying the terms we have:

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Hence, option: A is correct.

B)

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Hence, option: B is incorrect.

C)

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it could also be written as:

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Hence, option: C is correct.

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3a - 7 = 2(7a - 3)

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