Answer:
Step-by-step explanation:
(x^2+y^2)^2=(x^2)^2+2x^2y^2+(y^2)^2
Adding and substracting 2x^2y^2
We get
(x^2+y^2)^2=(x^2)^2+2x^2y^2+(y^2)^2 +2x^2y^2-2x^2y^2
And we know a^2-2ab+b^2=(a-b)^2
So we identify (x^2)^2 as a^2 ,(y^2)^2 as b^2 and -2x^2y^2 as - 2ab. So we can rewrite (x^2+y^2)^2=(x^2 - y^2)^2 + 2x^2y^2 + 2x^2y^2= (x^2 - y^2)^2+4x^2y^2= (x^2 - y^2)^2+2^2x^2y^2
Moreever we know (a·b·c)^2=a^2·b^2·c^2 than means 2^2x^2y^2=(2x·y)^2
And (x^2+y^2)^2=(x^2 - y^2)^2 + (2x·y)^2
Answer:
A) 10.7a - 8.1b
Step-by-step explanation:
(14.2a + 9.8b) - (13.1b - 0.2a) - (3.7a + 4.8b)
Combine like terms.
(14.2a + 0.2a - 3.7a) = 10.7a
(9.8b - 13.1b - 4.8b) = -8.1b
Answer:
Compare the values. 9x10^2 is <u><em>3x10^-4</em></u> times as much as 3x10^-2.
Step-by-step explanation:
If you have 9x10^2 divided by 3x10^-2, it would equal to A.
<h3>
Answer: A) zero velocity</h3>
Explanation:
Recall that the slope is equal to the rise/run.
Rise = change in y = change in distance
Run = change in x = change in time
If we have a horizontal line, then there is no change in y. The rise would be 0 here. The run can be anything you want. Let's just call it x
Slope = rise/run = 0/x = 0
Therefore, all horizontal lines have a slope of 0.
The slope of a distance time graph represents the velocity because
velocity = (change in distance)/(change in time) = rise/run = slope
for example, a velocity of 10 meters per second represents a change of 10 meters over 1 second. The rise here woud be 10 meters and the run would be 1 second.
Answer:
32
Step-by-step explanation:
