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andriy [413]
3 years ago
5

(1/4+1/4)-6÷1/3+2 how do you get it?????​

Mathematics
2 answers:
victus00 [196]3 years ago
8 0
2/4-6 ÷ 1/3 + 2
|
v
2/4 - 2 + 2
|
v
2/4 -0

=2/4 -> 1/2

you get it by using PEMDAS
Licemer1 [7]3 years ago
7 0

Answer:

decimal form: -15.5

exact form: -31/2

Step-by-step explanation: use the pemdas rule!

1Parenthesis

2Exponent

3Multiply

4Division

5Add

6Subtract

1st 1/4 + 1/4 = 0.5

2nd there is no exponents

3rd there is no multiplying

4rth -6÷1/3 = -18

5th 0.5-18 +2 add 2

last 0.5-16

=-15.5

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Given g(x) = 2x + 4, solve for x when g(x) = -8
Mnenie [13.5K]

Answer:

The value of  x = -6

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given that g(x) = 2 x + 4  and g (x ) = -8

⇒    Equating  

               2 x +4 = - 8

  Subtracting '4' on both sides, we get

              2 x + 4 - 4 = -8 -4

        ⇒  2 x + 0 = -12

       ⇒   2 x  = -12

<u><em>Step(ii):-</em></u>

Dividing '2' on both sides, we get

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4 0
3 years ago
For a standardized psychology examination intended for psychology majors, the historical data show that scores have a mean of 50
Volgvan

Answer:

P(\bar X>530)=1-0.808=0.192

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Let X the random variable that represent the scores, and for this case we know the distribution for X is given by:

X \sim N(\mu=505,\sigma=170)  

And let \bar X represent the sample mean, the distribution for the sample mean is given by:

\bar X \sim N(\mu,\frac{\sigma}{\sqrt{n}})

On this case  \bar X \sim N(505,\frac{170}{\sqrt{35}})

2) Calculate the probability

We want this probability:

P(\bar X>530)=1-P(\bar X

The best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}

If we apply this formula to our probability we got this:

P(\bar X >530)=1-P(Z

P(\bar X>530)=1-0.808=0.192

3 0
3 years ago
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<h2>PROBLEM SOLVING</h2>

__________________________

<h3>Given:</h3>
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