"Rotation and reflection" are the composition of transformations among the following choices given in the question that <span>will map figure K onto figure S and then onto figure U. The correct option among all the options that are given in the question is the second option or option "B". I hope that the answer has helped you. </span>

5 0

4 years ago

Read 2 more answers

Plz help its so confusing

aleksklad [387]

Answer:

20, 4

Step-by-step explanation:

Let's assume total number of students registered is n

Last week n/4 people are absent

so people present are n - n/4 = <u>3n/4</u>

Today after return of Jen 1/5 n are absent

so people present are n - n/5 = 4n/5

which is also equal to last week present people + 1 (Jen)

= 3n/4 + 1

= (3n + 4) / 4

so (3n + 4) / 4 = 4n/5

=> 3n + 4 = 4n/5 * 4

=> (3n + 4) * 5 = 16n

=> 15n + 20 = 16n

=> 20 = n

=> n = 20

So total students registered for class is 20

today no of people absent = n/5 = 20/5 = 4

8 0

3 years ago

GET 95 POINTS Let f(x) = 1/x and g(x)=x² + 6x. What

Dimas [21]

Answer:

hey there hope this answer helps you out

Step-by-step explanation:

we have two functions f(x) and g(x) such that

$f(x) = \frac{1}{x}$

and

$g(x) = {x}^{2} + 6x$

solving for f ° g, we'll substitute the x in f(x) by the value of g(x)

$fog = \frac{1}{g(x)}$

$fog \: = \frac{1}{ {x}^{2} + 6x }$

taking x common in denominator

$fog = \frac{1}{x(x + 6)}$

for a function to exist it should not have 0 in its denominator

checking the values of x for which the denominator of f ° g becomes 0 :-

x = 0 and
x = -6

so the function doesn't exist at values x = 0, -6

<h3>So, <u>0, -6</u> cannot be in the domain of f°g</h3>

5 0

3 years ago