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Anna71 [15]
2 years ago
11

Review

Mathematics
1 answer:
Doss [256]2 years ago
5 0
The answer is bbc or if that’s not the answer the then it’s bbl THANK ME LATERRRR
You might be interested in
What is the volume of a crude with a side length of 3 2/3 cm
IrinaK [193]

Answer:

Volume l^3 ,where l is the side of cube

11/3^3=1331/27

=49.29cm^3

4 0
3 years ago
Darla has written the numbers 1-12 on twelve cards of the same size. she picks two cards at random, without replacing the first
Vikki [24]
25% you are welcome thx me later
4 0
3 years ago
Help help help help help
Mkey [24]

Answer:

  x = 42

Step-by-step explanation:

The marked angles are supplementary, so their sum is 180°.

  (2x +8) +(2x +4) = 180

  4x +12 = 180 . . . . . . . . . simplify

  x +3 = 45 . . . . . . . divide by 4 (because we can)

  x = 42 . . . . . . subtract 3

_____

<em>Additional comment</em>

A "two-step" linear equation like this one is usually solved by subtracting the unwanted constant, then dividing by the coefficient of the variable. Here, we have done those steps in reverse order. This makes the numbers smaller and  eliminates the coefficient of the variable. Sometimes I find it easier to solve the equation this way.

5 0
2 years ago
Drag each tile to the correct box. Not all tiles will be used. Consider function f. f(x)=7x-21 Place the steps for finding in th
dimulka [17.4K]

x=7x-21

Step-by-step explanation:

  • x=7x-21
  • 21=7x-x
  • 21=6x
  • x=21/6
  • x=7/2
  • x=3.5
5 0
2 years ago
Select the correct expressions. 1 Identify each expression that represents the slope of a tangent to the curve y= * +1 at any po
Olegator [25]

The expressions which represents the slope of a tangent to the curve y=\frac{1}{x+1} at any point (x, y) are:

                                ​f'(x) =limh \rightarrow 0\frac{-h}{h(x+1)(x+h+1)}\\\\f'(x) =limh \rightarrow 0\frac{-h}{x^2h+2xh+xh^2+h^2 +1}

<h3>The slope of a tangent to the curve.</h3>

Mathematically, the slope of a tangent line to the curve is given by this equation:

f'(x) =limh \rightarrow 0\frac{f(x+h)-f(x)}{h}

Given the function:

f(x)=y=\frac{1}{x+1}

When (x + h), we have:

f(x+h)=y=\frac{1}{x+h+1}

Next, we would find the derivative of f(x):

f'(x) =limh \rightarrow 0\frac{\frac{1}{x+h+1} -\frac{1}{x+1}}{h}\\\\f'(x) =limh \rightarrow 0\frac{x+1 -(x+h+1)}{h(x+1)(x+h+1)}\\\\f'(x) =limh \rightarrow 0\frac{x+1 -x-h-1}{h(x+1)(x+h+1)}\\\\f'(x) =limh \rightarrow 0\frac{-h}{h(x+1)(x+h+1)}\\\\f'(x) =limh \rightarrow 0\frac{-h}{x^2h+2xh+xh^2+h^2 +1}\\\\f'(x) = \frac{-1}{(x+1)(x+1)} \\\\f'(x) = \frac{-1}{(x+1)^2}

Read more on slope of a tangent here: brainly.com/question/26015157

#SPJ1

5 0
2 years ago
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