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pav-90 [236]
2 years ago
13

Skate station charges a flat rate of $5.00 per day for skate rental plus $2.00 per hour of skating. If the number of hours is re

presented by "h," which algebraic expression represents the overall rate for "h" hours of skating?
5h
5 + 2h
5 + h
7h
Mathematics
1 answer:
mixas84 [53]2 years ago
7 0
The answer is 5+2h because it is $2 per hour so 2h and $5 per day. it does not have a variable for $5 per day so yeah.
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How were the latin american policies of president theodore roosevelt and president wilson similar
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Ultimately Woodrow Wilson's preferred direction was not to get involved with the internal affairs of the USA's near neighbors in Latin America. However events unfolded that meant his governments ended up being as interventionist as those of Teddy Roosevelt, for example occupying Haiti and the Dominican Republic. These activities were not intended plans of Wilson's in the way that Roosevelt set out to police Latin America but nonetheless the impact was the same.
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3 0
2 years ago
Find two power series solutions of the given differential equation about the ordinary point x = 0. compare the series solutions
monitta
I don't know what method is referred to in "section 4.3", but I'll suppose it's reduction of order and use that to find the exact solution. Take z=y', so that z'=y'' and we're left with the ODE linear in z:

y''-y'=0\implies z'-z=0\implies z=C_1e^x\implies y=C_1e^x+C_2

Now suppose y has a power series expansion

y=\displaystyle\sum_{n\ge0}a_nx^n
\implies y'=\displaystyle\sum_{n\ge1}na_nx^{n-1}
\implies y''=\displaystyle\sum_{n\ge2}n(n-1)a_nx^{n-2}

Then the ODE can be written as

\displaystyle\sum_{n\ge2}n(n-1)a_nx^{n-2}-\sum_{n\ge1}na_nx^{n-1}=0

\displaystyle\sum_{n\ge2}n(n-1)a_nx^{n-2}-\sum_{n\ge2}(n-1)a_{n-1}x^{n-2}=0

\displaystyle\sum_{n\ge2}\bigg[n(n-1)a_n-(n-1)a_{n-1}\bigg]x^{n-2}=0

All the coefficients of the series vanish, and setting x=0 in the power series forms for y and y' tell us that y(0)=a_0 and y'(0)=a_1, so we get the recurrence

\begin{cases}a_0=a_0\\\\a_1=a_1\\\\a_n=\dfrac{a_{n-1}}n&\text{for }n\ge2\end{cases}

We can solve explicitly for a_n quite easily:

a_n=\dfrac{a_{n-1}}n\implies a_{n-1}=\dfrac{a_{n-2}}{n-1}\implies a_n=\dfrac{a_{n-2}}{n(n-1)}

and so on. Continuing in this way we end up with

a_n=\dfrac{a_1}{n!}

so that the solution to the ODE is

y(x)=\displaystyle\sum_{n\ge0}\dfrac{a_1}{n!}x^n=a_1+a_1x+\dfrac{a_1}2x^2+\cdots=a_1e^x

We also require the solution to satisfy y(0)=a_0, which we can do easily by adding and subtracting a constant as needed:

y(x)=a_0-a_1+a_1+\displaystyle\sum_{n\ge1}\dfrac{a_1}{n!}x^n=\underbrace{a_0-a_1}_{C_2}+\underbrace{a_1}_{C_1}\displaystyle\sum_{n\ge0}\frac{x^n}{n!}
4 0
3 years ago
Please help with this
Blizzard [7]

The probability is 4:20

It is correct because there are 20 students and there could be 4 guesses

5 0
2 years ago
Please someone actually help :((( honestly im just gonna drop out
Lorico [155]

Answer:

12

Step-by-step explanation:

4u - 8u = -63 + 15 ( collecting like terms)

-4u = -48

u = 12

8 0
2 years ago
Read 2 more answers
Please help!!
liq [111]
The answer is B, 8x^2+32x+24
5 0
2 years ago
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