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jek_recluse [69]

2 years ago

15

9(8-x)=3x PLEASE SOLVE AND SHOW YOUR WORK PLS IN EXPLANATION IF YOU DO I WILL DEFINENTLY GIVE BRAINLIEST TYYYYYYYYYYYYYYYYYYYY :

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2 answers:

diamong [38]2 years ago

7 0

Using distribution you do 9*8=72 then 9*(-x)=-9x
72-9x=3x
In both sides +9x
72=12x
Divide by 12
X=6

sveta [45]2 years ago

4 0

9(8-x)=3x
72-9x=3x
72=12x
x=6

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Three lights all go on one changes every 5 sec one every 6 sec one every 8 sec when will they all go on together

inysia [295]

In order to calculate, you need to find their LCM
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So, That time will be 120 sec = 2 min.
In short, Your Final Answer would be 2 min.

Hope this helps!

3 0

3 years ago

WILL GIVE BRAINLY PLEASE HELPPPPP

erica [24]

Answer:

C

Step-by-step explanation:

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5 0

3 years ago

Read 2 more answers

A national grocery store chain wants to test the difference in the average weight of turkeys sold in Detroit and the average wei

Arte-miy333 [17]

Answer:

<em>Calculated value t = 1.3622 < 2.081 at 0.05 level of significance with 42 degrees of freedom</em>

<em>The null hypothesis is accepted . </em>

<em>Assume the population variances are approximately the same</em>

<u><em>Step-by-step explanation:</em></u>

<u>Explanation</u>:-

Given data a random sample of 20 turkeys sold at the chain's stores in Detroit yielded a sample mean of 17.53 pounds, with a sample standard deviation of 3.2 pounds

<em>The first sample size 'n₁'= 20</em>

<em>mean of the first sample 'x₁⁻'= 17.53 pounds</em>

<em>standard deviation of first sample S₁ = 3.2 pounds</em>

Given data a random sample of 24 turkeys sold at the chain's stores in Charlotte yielded a sample mean of 14.89 pounds, with a sample standard deviation of 2.7 pounds

<em>The second sample size n₂ = 24</em>

<em>mean of the second sample "x₂⁻"= 14.89 pounds</em>

<em>standard deviation of second sample S₂ = 2.7 poun</em>ds

<u><em>Null hypothesis</em></u><u>:-</u><u><em>H₀</em></u><em>: The Population Variance are approximately same</em>

<u><em>Alternatively hypothesis</em></u><em>: H₁:The Population Variance are approximately same</em>

<em>Level of significance ∝ =0.05</em>

<em>Degrees of freedom ν = n₁ +n₂ -2 =20+24-2 = 42</em>

<em>Test statistic :-</em>

<em> </em> $t = \frac{x^{-} _{1} - x_{2} }{\sqrt{S^2(\frac{1}{n_{1} } }+\frac{1}{n_{2} } }$

<em> where </em> $S^{2} = \frac{n_{1} S_{1} ^{2}+n_{2}S_{2} ^{2} }{n_{1} +n_{2} -2}$

$S^{2} = \frac{20X(3.2)^2+24X(2.7)^2}{20+24-2}$

<em> substitute values and we get S² = 40.988</em>

<em> </em> $t= \frac{17.53-14.89 }{\sqrt{40.988(\frac{1}{20} }+\frac{1}{24} )}$ <em></em>

<em> </em> t = 1.3622

Calculated value t = 1.3622

Tabulated value 't' = 2.081

Calculated value t = 1.3622 < 2.081 at 0.05 level of significance with 42 degrees of freedom

<u><em>Conclusion</em></u>:-

<em>The null hypothesis is accepted </em>

<em>Assume the population variances are approximately the same.</em>

<em> </em>

<em> </em>

<em> </em>

6 0

3 years ago

Cole says that all quadrilaterals are polygons but not all polygons are quadrilaterals is he correct explain��

zepelin [54]

YES, this is correct. All quadrilaterals whether is a trapezoid, parallelogram, rhombus and others, they are all polygons and all they have 4 sides and 4 angles. We know that a polygon is a figure with at least three sides and three angles.

Not all polygons are quadrilateral, this is also correct since some polygons have five or more sides and angles.

7 0

3 years ago

Help needed! How do I solve this?<br>Excuse the answers that are already in there!

anastassius [24]

1) 108
2) 72
3) 36
4) 72
5) 72
6) 144
7) 72
8) 72
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10) 108
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8 0

3 years ago