Answer:
<u>x-intercept</u>
The point at which the curve <u>crosses the x-axis</u>, so when y = 0.
From inspection of the graph, the curve appears to cross the x-axis when x = -4, so the x-intercept is (-4, 0)
<u>y-intercept</u>
The point at which the curve <u>crosses the y-axis</u>, so when x = 0.
From inspection of the graph, the curve appears to cross the y-axis when y = -1, so the y-intercept is (0, -1)
<u>Asymptote</u>
A line which the curve gets <u>infinitely close</u> to, but <u>never touches</u>.
From inspection of the graph, the curve appears to get infinitely close to but never touches the vertical line at x = -5, so the vertical asymptote is x = -5
(Please note: we cannot be sure that there is a horizontal asymptote at y = -2 without knowing the equation of the graph, or seeing a larger portion of the graph).
Answer:
Any point on the circle (x + 1)² + (y - 5)² = 2 with center (-1 , 5) and radius √2
Step-by-step explanation:
circle: (x + 1)² + (y - 5)² = 2
Less for statement 1 and less for statement 2
It should just be 3 15/16 because you can’t really simplify 15/16 because it’ll just give you decimals. For example; 15/3 is 5 but 16/3 is 5.333.... and 15/5 is 3 and 16/5 is 3.2, and 15/2 is 7.5 and that won’t work because it turns into a decimal.
To solve this problem you must think in this way.
First we see that function y is greater than 3-x, conclusion is the following
shaded area must be above function. That condition is satisfied by the graph 3 and 4.
Then we write inequality in the slope form y> -x+3.
We see that the coefficient of direction is -1 (negative) which mean that the graph is decreasing. That condition is satisfied by the graph No 4.
The correct answer is graph number 4 ( or D.)
Good luck!!!
