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dusya [7]
3 years ago
12

The ages in years of 21 people in a swimming pool are displayed in the stem-and-leaf plot. Determine the median age of

Mathematics
1 answer:
LenaWriter [7]3 years ago
5 0

Answer:

<h3>5 years</h3>

Step-by-step explanation:

To get the median of the ages given

2, 4, 5, 6, 7, 8, 8, 8, 0, 3, 5, 9, 1, 4, 7, 6, 1, 2, 4, 4, 8

First we will need to rearrange the median ages in ascending order (from lowest to highest)

0, 1, 1, 2, 2, 3, 4, 4, 4, 4, 5, 5, 6, 6, 7, 7, 8, 8, 8, 8, 9

Next is to locate the middle value of the arranged data

(0, 1, 1, 2, 2, 3, 4, 4, 4, 4), 5, (5, 6, 6, 7, 7, 8, 8, 8, 8, 9)

The total values in both parenthesis are the same(10 in numbers) leaving 5 as the middle number.

Hence the median age of the people in the pool is 5years

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What is the value of 5^3i^9
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Answer:

5^(3)i^(9)= five cubes times i to the power of 9=125i

Step-by-step explanation:

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4 0
2 years ago
Problem PageQuestion Calcium levels in people are normally distributed with a mean of mg/dL and a standard deviation of mg/dL. I
SIZIF [17.4K]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The  calcium level that is the borderline between low calcium levels and those not considered low is  c = 8.68

Step-by-step explanation:

From the question we are told that

    The mean is  \mu =  9.5\  mg/dL

     The standard deviation \sigma =  0.5 \ mg/dL

    The proportion of the population with low calcium level is  p =5% = 0.05

Let X be a X random calcium level

  Now the  P(X < c) = 0.05

Here P denotes probability

        c is population with calcium level at the borderline

  Since the calcium level is normally distributed the z-value is  evaluated as

    P(Z < \frac{c - \mu}{\sigma } ) = 0.05

The critical value for 0.05 from the standard normal distribution table is

       t_{0.05} = -1.645

=>    \frac{c - \mu}{\sigma }  =  -1.645

substituting values

       \frac{c - 9.5}{0.5 }  =  -1.645

=>    c - 9.5 =  -0.8225

=>     c = 8.68

 

6 0
3 years ago
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