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dusya [7]
3 years ago
12

The ages in years of 21 people in a swimming pool are displayed in the stem-and-leaf plot. Determine the median age of

Mathematics
1 answer:
LenaWriter [7]3 years ago
5 0

Answer:

<h3>5 years</h3>

Step-by-step explanation:

To get the median of the ages given

2, 4, 5, 6, 7, 8, 8, 8, 0, 3, 5, 9, 1, 4, 7, 6, 1, 2, 4, 4, 8

First we will need to rearrange the median ages in ascending order (from lowest to highest)

0, 1, 1, 2, 2, 3, 4, 4, 4, 4, 5, 5, 6, 6, 7, 7, 8, 8, 8, 8, 9

Next is to locate the middle value of the arranged data

(0, 1, 1, 2, 2, 3, 4, 4, 4, 4), 5, (5, 6, 6, 7, 7, 8, 8, 8, 8, 9)

The total values in both parenthesis are the same(10 in numbers) leaving 5 as the middle number.

Hence the median age of the people in the pool is 5years

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Solve the Inequality Give 5 solutions of the inequality ( Show your solution).<br> 2x -3 &lt; 5
marysya [2.9K]

Answer:

Inequality Form:

x<4

1<4

3<4

-1004<4

Interval Notation:

(−∞,4)

(-1004,4)

(3,4)

(1,4)

Step-by-step explanation:

5 0
3 years ago
You fly a helicopter for 20 minutes that goes at a speed of 240 km per hour. How far did you go?
Stells [14]

Answer:

4800 km

Step-by-step explanation:

240*20=4800

4 0
3 years ago
Find the work required to move an object in the force field F = ex+y &lt;1,1,z&gt; along the straight line from A(0,0,0) to B(-1
storchak [24]

Answer:

Work = e+24

F is not conservative.

Step-by-step explanation:

To find the work required to move an object in the force field  

\large F(x,y,z)=(e^{x+y},e^{x+y},ze^{x+y})

along the straight line from A(0,0,0) to B(-1,2,-5), we have to parameterize this segment.

Given two points P, Q in any euclidean space, you can always parameterize the segment of line that goes from P to Q with

r(t) = tQ + (1-t)P with 0 ≤ t ≤ 1

so  

r(t) = t(-1,2,-5) + (1-t)(0,0,0) = (-t, 2t, -5t)  with 0≤ t ≤ 1

is a parameterization of the segment.

the work W required to move an object in the force field F along the straight line from A to B is the line integral

\large W=\int_{C}Fdr

where C is the segment that goes from A to B.

\large \int_{C}Fdr =\int_{0}^{1}F(r(t))\circ r'(t)dt=\int_{0}^{1}F(-t,2t,-5t)\circ (-1,2,-5)dt=\\\\=\int_{0}^{1}(e^t,e^t,-5te^t)\circ (-1,2,-5)dt=\int_{0}^{1}(-e^t+2e^t+25te^t)dt=\\\\\int_{0}^{1}e^tdt-25\int_{0}^{1}te^tdt=(e-1)+25\int_{0}^{1}te^tdt

Integrating by parts the last integral:

\large \int_{0}^{1}te^tdt=e-\int_{0}^{1}e^tdt=e-(e-1)=1

and  

\large \boxed{W=\int_{C}Fdr=e+24}

To show that F is not conservative, we could find another path D from A to B such that the work to move the particle from A to B along D is different to e+24

Now, let D be the path consisting on the segment that goes from A to (1,0,0) and then the segment from (1,0,0) to B.

The segment that goes from A to (1,0,0) can be parameterized as  

r(t) = (t,0,0) with 0≤ t ≤ 1

so the work required to move the particle from A to (1,0,0) is

\large \int_{0}^{1}(e^t,e^t,0)\circ (1,0,0)dt =\int_{0}^{1}e^tdt=e-1

The segment that goes from (1,0,0) to B can be parameterized as  

r(t) = (1-2t,2t,-5t) with 0≤ t ≤ 1

so the work required to move the particle from (1,0,0) to B is

\large \int_{0}^{1}(e,e,-5et)\circ (-2,2,-5)dt =25e\int_{0}^{1}tdt=\frac{25e}{2}

Hence, the work required to move the particle from A to B along D is

 

e - 1 + (25e)/2 = (27e)/2 -1

since this result differs from e+24, the force field F is not conservative.

6 0
4 years ago
If p=2 and q= 5, is the value of p/q equivalent to 2/5
PIT_PIT [208]

Answer:

Yes it is

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
2x to the power of 3+7x to the power of 2-2 divided by x-2=
egoroff_w [7]

Answer:

9x^5 -1

Step-by-step explanation:

2x^3+7x^2-2 / -2

9x^5-2/2

9x^5 -1

5 0
3 years ago
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