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3 years ago

A map has a scale of 1 in : 3 km. If the actual distance is 15 km, what is the distance on the map?

Mathematics

1 answer:

Black_prince [1.1K]3 years ago

4 0

Answer:

5 in.

Step-by-step explanation:

The ratio of map distance to real distance is 1 in : 3 km meaning that 1 inch on the map describes 15 km in real life.

15 km is 5 times 3 km, so the map distance is 5 times 1 in., or 5 in.

1 in. x 5 : 3 km x 5

This is a "school math" problem where things come out nicely! Another way to look at this is with equivalent fractions.

$\frac{\text{1 in}}{\text{5 km}} = \frac{\text{m}}{\text{15 km}}$

"cross multiply"

$5m = (15)(1)\\5m=15\\m=3 \text{ in.}$

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Find the locus of a point such that the sum of its distance from the point ( 0 , 2 ) and ( 0 , -2 ) is 6.

jok3333 [9.3K]

Answer:

$\displaystyle \frac{x^2}{5}+\frac{y^2}{9}=1$

Step-by-step explanation:

We want to find the locus of a point such that the sum of the distance from any point P on the locus to (0, 2) and (0, -2) is 6.

First, we will need the distance formula, given by:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Let the point on the locus be P(x, y).

So, the distance from P to (0, 2) will be:

$\begin{aligned} d_1&=\sqrt{(x-0)^2+(y-2)^2}\\\\ &=\sqrt{x^2+(y-2)^2}\end{aligned}$

And, the distance from P to (0, -2) will be:

$\displaystyle \begin{aligned} d_2&=\sqrt{(x-0)^2+(y-(-2))^2}\\\\ &=\sqrt{x^2+(y+2)^2}\end{aligned}$

So sum of the two distances must be 6. Therefore:

$d_1+d_2=6$

Now, by substitution:

$(\sqrt{x^2+(y-2)^2})+(\sqrt{x^2+(y+2)^2})=6$

Simplify. We can subtract the second term from the left:

$\sqrt{x^2+(y-2)^2}=6-\sqrt{x^2+(y+2)^2}$

Square both sides:

$(x^2+(y-2)^2)=36-12\sqrt{x^2+(y+2)^2}+(x^2+(y+2)^2)$

We can cancel the x² terms and continue squaring:

$y^2-4y+4=36-12\sqrt{x^2+(y+2)^2}+y^2+4y+4$

We can cancel the y² and 4 from both sides. We can also subtract 4y from both sides. This leaves us with:

$-8y=36-12\sqrt{x^2+(y+2)^2}$

We can divide both sides by -4:

$2y=-9+3\sqrt{x^2+(y+2)^2}$

Adding 9 to both sides yields:

$2y+9=3\sqrt{x^2+(y+2)^2}$

And, we will square both sides one final time.

$4y^2+36y+81=9(x^2+(y^2+4y+4))$

Distribute:

$4y^2+36y+81=9x^2+9y^2+36y+36$

The 36y will cancel. So:

$4y^2+81=9x^2+9y^2+36$

Subtracting 4y² and 36 from both sides yields:

$9x^2+5y^2=45$

And dividing both sides by 45 produces:

$\displaystyle \frac{x^2}{5}+\frac{y^2}{9}=1$

Therefore, the equation for the locus of a point such that the sum of its distance to (0, 2) and (0, -2) is 6 is given by a vertical ellipse with a major axis length of 3 and a minor axis length of √5, centered on the origin.

5 0

3 years ago

Read 2 more answers

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Setler79 [48]

$62.9 - 22.11$

7 0

4 years ago

Read 2 more answers

Convert these unlike fractions to equivalent like fractions and add them. You must use the LCD to get the answer correct. If pos

Gnoma [55]

The converted fractions are 3/12 and 5/12 and the sum is 2/3

<h3>How to convert the fractions?</h3>

From the question, the fractions are given as

1/4 and 5/12

The denominators of these fractions are

4 and 12

So. we start by calculating the LCD of the denominators

So, we have

4 = 2* 2

12 = 2 * 2 * 3

This gives

LCD = 2 * 2 * 3

Evaluate

LCD = 12

This means that the common denominator must be 12

So, we have

1/4 and 5/12

Multiply 1/4 by 3/3

This gives

3/12 and 5/12

When the fractions are added, we have

3/12 + 5/12 = (3 + 5)/12

Evaluate

3/12 + 5/12 = 8/12

Reduce fraction

3/12 + 5/12 = 2/3

Hence, the sum of the fractions is 2/3

Read more about fractions at

brainly.com/question/1622425

#SPJ1

8 0

1 year ago

Emily has x amounts of apples, Peter has 4 apples less than Emily and Joshua has 2 times the number of apples of Peter. The tota

VladimirAG [237]

Answer:

Emily: 13, Peter: 9, Joshua: 18

Step-by-step explanation:

Emily = x

Peter = Emily - 4 = x - 4

Joshua = 2(Peter) = 2(x - 4)

Total = 40 = Emily + Peter + Joshua = (x) + (x - 4) + 2(x - 4)

40 = 2x - 4 + 2x -8

40 = 4x - 4 - 8

40 = 4x - 12

52 = 4x

x = 13

Emily = 13

Peter = 13 - 4 = 9

Joshua = 2(13 - 4) = 2(9) = 18

13 + 9 +18 = 40

5 0

2 years ago

How do you you divide 67by6

Law Incorporation [45]

You first set it up as long division.
Second you would find out how many times 6 goes into 67, so count by 6's until you get close 67.
Third once you get that number you write it on top of the long division and then you would subtract whatever that number is below which is 66 because 6 * 11= 66.
So then you would subtract 67 minus 66 which would be 1. Then go from there and you'll get your answer.

Hope this helps!

6 0

4 years ago