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sattari [20]
2 years ago
15

What is the constant term in the expression? 15a + 10b + 5 – 7b

Mathematics
1 answer:
MA_775_DIABLO [31]2 years ago
4 0

Answer:

5

Step-by-step explanation:

15a , 10b , and -7b are coefficients.

You might be interested in
Write the ordered pair that represents MP. Then find the magnitude of MP.
jarptica [38.1K]

Answer:

(23,-4):\sqrt{545} units

Step-by-step explanation:

We are given that M(-19,4)and P(4,0)

We have to find the ordered pair that represents MP and find the magnitude of MP.

MP=P-M

MP=(4,0)-(-19,4)=(4+19,0-4)

MP=(23,-4)

Magnitude of MP=\sqrt{(23)^2+(-4)^2}

Magnitude of MP=\sqrt{529+16}

Magnitude of MP=\sqrt{545} units

Hence, .option c is true.

Answer:c.(23,-4):\sqrt{545} units

5 0
3 years ago
At what point of the curve y = cosh(x does the tangent have slope 2?
Dahasolnce [82]
The hyperbolic cos (cosh) is given by
cosh (x) = (e^x + e^-x) / 2
The slope of a tangent line to a function at a point is given by the derivative of that function at that point.
d/dx [cosh(x)] = d/dx[(e^x + e^-x) / 2] = (e^x - e^-x) / 2 = sinh(x)
Given that the slope is 2, thus
sinh(x) = 2
x = sinh^-1 (2) = 1.444

Therefore, the curve of y = cosh(x) has a slope of 2 at point x = 1.44
5 0
2 years ago
Can u plz help me plz?
mina [271]

6^3

that's the answer

8 0
3 years ago
What is the answer plzzzzzz help a kid out
Komok [63]

Answer:

the answer is 8 by one of this question.

4 0
3 years ago
Find an expression for the function f(x) whose graph is a line passing through the points (8,-5) and (-9,2). f(x)=
kolbaska11 [484]

Answer: f(x) = - 7x/17 - 29/17

Step-by-step explanation:

The expression for the function f(x) would be represented in the slope-intercept form, y = mx + c

Where

c represents the y intercept.

m represents the slope of the line.

Slope, m =change in value of y on the vertical axis / change in value of x on the horizontal axis represent

change in the value of y = y2 - y1

Change in value of x = x2 -x1

The line passes through (8, - 5) and (- 9, 2),

y2 = 2

y1 = - 5

x2 = - 9

x1 = 8

Slope,m = ( 2 - - 5)/(- 9 - 8) = 7/- 17 =

- 7/17

To determine the intercept, we would substitute x = 8, y = - 5 and m = - 7/17 into

y = mx + c. It becomes

- 5 = - 7/17 × 8 + c

- 5 = - 56/17 + c

c = - 5 + 56/17

c = - 29/17

The equation becomes

f(x) = - 7x/17 - 29/17

8 0
3 years ago
Read 2 more answers
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