Write the quadratic equation the has the roots (-1-√2)/3 and (-1+√2)/3 if its coefficient with x^2 is equal to...1
1 answer:
Step-by-step explanation:
x1+x2 = (-1-√2)/3 + (-1+√2)/3
= -2/3
(x1) (x2) = (-1-√2)/3 × (-1+√2)/3
= -1/9
the equation :
x² -(-2/3)x + (-1/9) = 0
x ² + ⅔ x - 1 / 9 = 0
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I plugged -6 in for y and then simplified. -6 x -6 = 36. 7 x -6 = -42. So 36 - 42 = -6. -6 + 4 = -2
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