1/5(6+3+1)^2
1/5 x 10^2
1/5 x 100
answer: 20
<span>f(x) = x^2 + 1
f(1) = 1</span>^2 + 1 = 2
so 2f(1) = 2(2) = 4
<span>g(x) = 3x + 1
f(4) = 3(4) + 1 = 13
</span>3g(4) = 3(13) = 39
<span> 2f(1) + 3g(4) = 4 + 39 = 43
</span>
answer
<span>2. 43</span>
Answer:
10√2
Step-by-step explanation:
Lets cut the square into a triangle, making a line from one corner to another, then let's see what we have.
We shoupd have a triangle where we don't know the hypotenuse, which we can find using the formula: a^2 + b^2 = c^2
so:
10^2 + 10^2 = c^2
100 + 100 = c^2
c^2 = 200
now let's square root what we got
√200
there are 2 10's in 200, which will turn the equation to:
10√2
this can't be simplified further, so our answer is 10√2
The most convenient way to capture 
is with the parameterization
so we only need one iterated integral.
Compute the integral with respect to 
.
Compute the remaining integral.
If we had chosen the opposite order of variables, we would have used
where
so we would have needed two iterated integrals,
Answer:
Yes, distance is never negative.
