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3 years ago

Simplify ((a³ - 27) / (a - 3)) (a² - 3a + 9)

Mathematics

1 answer:

Sonja [21]3 years ago

6 0

Answer:

$a^{4}$ +9a²+81

Step-by-step explanation:

((a³ - 27) / (a - 3)) (a² - 3a + 9)

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Find the measure of the exterior angle.

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125

Step-by-step explanation:

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3 years ago

Find the mass of the triangular region with vertices (0, 0), (3, 0), and (0, 1), with density function ρ(x,y)=x2+y2.

ololo11 [35]

Since density is the ratio of mass to (in this case) area, we can find the mass of the triangular region $\mathcal T$ by computing the double integral of the density function over $\mathcal T$ :

$\mathrm{mass}=\displaystyle\iint_{\mathcal T}\rho(x,y)\,\mathrm dx\,\mathrm dy$

The boundary of $\mathcal T$ is determined by a set of lines in the $x,y$ plane. One way to describe the region $\mathcal T$ is by the set of points,

$\mathcal T=\left\{(x,y)\mid0\le x\le 3\,\land\,0\le y\le1-\dfrac x3\right\}$

So the mass is

$\mathrm{mass}=\displaystyle\int_{x=0}^{x=3}\int_{y=0}^{y=1-x/3}(x^2+y^2)\,\mathrm dy\,\mathrm dx$

$=\displaystyle\int_{x=0}^{x=3}\left(x^2y+\frac{y^3}3\right)\bigg|_{y=0}^{y=1-x/3}\,\mathrm dx$

$=\displaystyle\int_{x=0}^{x=3}\left(x^2\left(1-\frac x3\right)+\frac{\left(1-\frac x3\right)^3}3\right)\,\mathrm dx$

$=\displaystyle\frac1{81}\int_0^3(27-27x+90x^2-28x^3)\,\mathrm dx=\frac52$

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3 years ago

Help me it's too urgent

xxTIMURxx [149]

Answer:

id k if it's right but i hope this helps :)

Step-by-step explanation:

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3 years ago

Simplify ((a³ - 27) / (a - 3)) (a² - 3a + 9)​

Simplify ((a³ - 27) / (a - 3)) (a² - 3a + 9)