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fiasKO [112]
2 years ago
12

Translate each into an algebraic expression

Mathematics
2 answers:
Makovka662 [10]2 years ago
5 0

Answer:

A) 5k

Step-by-step explanation:

anything near a number like that is usually times. Like 7g would be 7xg!

Vera_Pavlovna [14]2 years ago
5 0
5(k/5)(5-k)/1 I’m pretty sure
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What is the midpoint of the line segment with endpoints(-2,-2) and (4,6)
Ann [662]

Answer:

The midpoint of points (-2,-2)\ and\ (4,6) is (1,2).

Step-by-step explanation:

Given points are (-2,-2)\ and\ (4,6). We need to find the midpoint of the line segment.

The formula of finding midpoints between the point (x_1,y_1)\ and\ (x_2,y_2) is

(\frac{x_1+x_2}{2}),(\frac{y_1+y_2}{2})\ Equation(1)

W have points (x_1,y_1)=(-2,-2). And (x_2,y_2)=(4,6)

Let us plug the value in Equation (1)

(\frac{-2+4}{2} ),(\frac{-2+6}{2})

(\frac{2}{2}),(\frac{4}{2})\\ \\(1,2)

So, the midpoint of points (-2,-2)\ and\ (4,6) is (1,2).

3 0
3 years ago
Please help me with 11 and 12. The first best answer gets brainlist.
ololo11 [35]
Bracelet

There are 2 bracelets and she possibly picks three. :)
5 0
3 years ago
What is the angle of rotation of the minute hand of a clock moving from 6:10 to 7:00?
german
Thank you for posting your question here at brainly. Feel free to ask more questions.  

The best and most correct answer among the choices provided by the question is <span>D.300°</span>.<span>       
    </span><span>
Hope my answer would be a great help for you.</span>
7 0
2 years ago
A researcher surveyed 150 high school students and found that 68% played a musical insturment. What would be a reasonable range
maria [59]

Answer:

The reasonable range for the population mean is (61%, 75%).

Step-by-step explanation:

The interval estimate of a population parameter is an interval of values that consist of the values within which the true value of the parameter lies with a certain probability.

The mean of the sampling distribution of sample proportion is, \hat p.

One of the best interval estimate of population proportion is the 95% confidence interval for proportion,

CI=\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

Given:

n = 150

\hat p = 0.68

The critical value of <em>z</em> for 95% confidence level is:

z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

Compute the 95% confidence interval for proportion as follows:

CI=\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

     =0.68\pm1.96\sqrt{\frac{0.68(1-0.68)}{150}}\\\\=0.68\pm 0.0747\\\\=(0.6053, 0.7547)\\\\\approx (0.61, 0.75)

Thus, the reasonable range for the population mean is (61%, 75%).

5 0
3 years ago
Please help, I I beg you please
Tatiana [17]

Answer:

<em>The volume of the cube is </em> \mathit{\frac{27}{z^3x^{9}}} <em>cu in.</em>

Step-by-step explanation:

<u>The Volume of a Cube</u>

Let's have a cube of side length a. The volume of the cube is:

V=a^3

The cube of the image has a side length of

\displaystyle a=\frac{3x^{-3}}{z}\ inches

Simplifying the expression of the base by converting the negative exponent in the numerator to the denominator:

\displaystyle a=\frac{3}{zx^{3}}\ inches

Now find the volume:

\displaystyle V=\left(\frac{3}{zx^{3}}\ inches\right)^3

Applying the exponents:

\displaystyle V=\frac{3^3}{z^3x^{9}}\ inches^3

\displaystyle V=\frac{27}{z^3x^{9}}\ inches^3

The volume of the cube is \mathbf{\frac{27}{z^3x^{9}}} cu in.

8 0
3 years ago
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