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3 years ago

10

Simplify the expression 4+(9+x).

1 answer:

Anna11 [10]3 years ago

8 0

The answer is 36+4x u want me to explain?

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Pls help i will give brainliest

zlopas [31]

It is B because yiu solve

3 0

3 years ago

Please help I have an exam tomorrow!!!!

Zepler [3.9K]

I think the most appropriate answer would be "-6.58".

I hope it helped you!

5 0

3 years ago

What a Expression that has a value -8

kirill [66]

Answer:

(-4+2*2)+8

Step-by-step explanation:

2*2=4

-4+4= 0

0+8= -8

5 0

3 years ago

Read 2 more answers

The point P(1,1/2) lies on the curve y=x/(1+x). (a) If Q is the point (x,x/(1+x)), find the slope of the secant line PQ correct

lukranit [14]

Answer:

See explanation

Step-by-step explanation:

You are given the equation of the curve

$y=\dfrac{x}{1+x}$

Point $P\left(1,\dfrac{1}{2}\right)$ lies on the curve.

Point $Q\left(x,\dfrac{x}{1+x}\right)$ is an arbitrary point on the curve.

The slope of the secant line PQ is

$\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{\frac{x}{1+x}-\frac{1}{2}}{x-1}=\dfrac{\frac{2x-(1+x)}{2(x+1)}}{x-1}=\dfrac{\frac{2x-1-x}{2(x+1)}}{x-1}=\\ \\=\dfrac{\frac{x-1}{2(x+1)}}{x-1}=\dfrac{x-1}{2(x+1)}\cdot \dfrac{1}{x-1}=\dfrac{1}{2(x+1)}\ [\text{When}\ x\neq 1]$

1. If x=0.5, then the slope is

$\dfrac{1}{2(0.5+1)}=\dfrac{1}{3}\approx 0.3333$

2. If x=0.9, then the slope is

$\dfrac{1}{2(0.9+1)}=\dfrac{1}{3.8}\approx 0.2632$

3. If x=0.99, then the slope is

$\dfrac{1}{2(0.99+1)}=\dfrac{1}{3.98}\approx 0.2513$

4. If x=0.999, then the slope is

$\dfrac{1}{2(0.999+1)}=\dfrac{1}{3.998}\approx 0.2501$

5. If x=1.5, then the slope is

$\dfrac{1}{2(1.5+1)}=\dfrac{1}{5}\approx 0.2$

6. If x=1.1, then the slope is

$\dfrac{1}{2(1.1+1)}=\dfrac{1}{4.2}\approx 0.2381$

7. If x=1.01, then the slope is

$\dfrac{1}{2(1.01+1)}=\dfrac{1}{4.02}\approx 0.2488$

8. If x=1.001, then the slope is

$\dfrac{1}{2(1.001+1)}=\dfrac{1}{4.002}\approx 0.2499$

7 0

3 years ago

There are 3 people pulling on an object, the first person pulls with a force of 226 newtons at a direction of 145 degrees the se

Alona [7]

Answer:

$R=883.74N$

Step-by-step explanation:

From the question we are told that:

Force 1 $F_1=226N$

Force 2 $F_2=331N$

Force 3 $F_3=377N$

Direction 1 $\theta_1=145 degrees \approx 35 \textdegree (2nd qudrant)$

Direction 2 $\theta_2=303 degrees \approx 57 \textdegree (3rd qudrant)$

Direction 3 $\theta_3=77 degrees$

Generally Resolving forces to X axis is mathematically given by

$\sum f_x=337cos77+331cos57+226sin35$

$\sum f_x=351.596N$

Generally Resolving forces to Y axis is mathematically given by

$\sum f_y=337sin77+331sin57+226cos35$

$\sum f_x=810.788N$

Generally the equation for Resultant force R is mathematically given by

$R=\sqrt{\sum f_x^2+\sum f_x^2}$

$R=\sqrt{351.596^2+810.788^2}$

$R=883.74N$

7 0

3 years ago