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2 years ago

7

Sam bought a jacket marked $85.00 and a sweater marked $60.00. If the store was having a 20% off sale on all items, how many dol

lars did Sam save?

1 answer:

DENIUS [597]2 years ago

8 0

Answer:

he saved $7.25 Dollars

Step-by-step explanation:

$85 .00÷20% = 4.25 + $60.00 ÷ 20% = 3

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Please help with the picture below

elena-s [515]

Answer:

Step-by-step explanation:

Remark

The angles are marked as alternate interior angles. To be parallel, they must be equal. In other words x - 20 must equal 52. That's all you have to do. Just equate the 2 givens and solve.

Givens

x - 20 is one angle

52 is the other.

Solution

x - 20 = 52 Add 20 to both sides.

x - 20 + 20 = 52 +20 Combine

x = 72

Answer: C

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2 years ago

If Levi purchased a total of 50 ride tickets and game tickets at the amusement park and spent $29. If right tickets cost $.75 ea

erica [24]

Answer: he purchased 16 ride tickets.

Step-by-step explanation:

Let x represent the number of ride tickets that he purchased.

Let y represent the number of game tickets that he purchased.

Levi purchased a total of 50 ride tickets and game tickets at the amusement park. It means that

x + y = 50

If ride tickets cost $.75 each and game tickets cost $.50 each and the total amount spent on the tickets is $29, it means that

0.75x + 0.5y = 29- - - - - - - - - - - -1

Substituting x = 50 - y into equation 1, it becomes

0.75(50 - y) + 0.5y = 29

37.5 - 0.75y + 0.5y = 29

- 0.75y + 0.5y = 29 - 37.5

- 0.25y = - 8.5

y = - 8.5/-0.25

y = 34

x = 50 - y = 50 - 34

x = 16

5 0

2 years ago

Let f(x,y,z) = ztan-1(y2) i + z3ln(x2 + 1) j + z k. find the flux of f across the part of the paraboloid x2 + y2 + z = 3 that li

Sophie [7]

Consider the closed region $V$ bounded simultaneously by the paraboloid and plane, jointly denoted $S$ . By the divergence theorem,

$\displaystyle\iint_S\mathbf f(x,y,z)\cdot\mathrm dS=\iiint_V\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV$

And since we have

$\nabla\cdot\mathbf f(x,y,z)=1$

the volume integral will be much easier to compute. Converting to cylindrical coordinates, we have

$\displaystyle\iiint_V\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV=\iiint_V\mathrm dV$
$=\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=1}\int_{z=2}^{z=3-r^2}r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta$
$=\displaystyle2\pi\int_{r=0}^{r=1}r(3-r^2-2)\,\mathrm dr$
$=\dfrac\pi2$

Then the integral over the paraboloid would be the difference of the integral over the total surface and the integral over the disk. Denoting the disk by $D$ , we have

$\displaystyle\iint_{S-D}\mathbf f\cdot\mathrm dS=\frac\pi2-\iint_D\mathbf f\cdot\mathrm dS$

Parameterize $D$ by

$\mathbf s(u,v)=u\cos v\,\mathbf i+u\sin v\,\mathbf j+2\,\mathbf k$
$\implies\mathbf s_u\times\mathbf s_v=u\,\mathbf k$

which would give a unit normal vector of $\mathbf k$ . However, the divergence theorem requires that the closed surface $S$ be oriented with outward-pointing normal vectors, which means we should instead use $\mathbf s_v\times\mathbf s_u=-u\,\mathbf k$ .

Now,

$\displaystyle\iint_D\mathbf f\cdot\mathrm dS=\int_{u=0}^{u=1}\int_{v=0}^{v=2\pi}\mathbf f(x(u,v),y(u,v),z(u,v))\cdot(-u\,\mathbf k)\,\mathrm dv\,\mathrm du$
$=\displaystyle-4\pi\int_{u=0}^{u=1}u\,\mathrm du$
$=-2\pi$

So, the flux over the paraboloid alone is

$\displaystyle\iint_{S-D}\mathbf f\cdot\mathrm dS=\frac\pi2-(-2\pi)=\dfrac{5\pi}2$

6 0

3 years ago

Solve ASAP<br>i dont get it

andreev551 [17]

The slope is the coefficient of x when the coefficient of y is 1.
The slope is -0.5
The y-intercept is where x=0
y = 17 - 0.5 (0)
y = 17
The y-intercept is 17.

5 0

3 years ago

Find the product.<br> 3cd^2(6cd + 14cd^2)

klasskru [66]

3cd^2(6cd + 14cd^2)
18cd^3 + 42cd^4

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3 years ago