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KiRa [710]
3 years ago
14

A grocery store stocks shelves with 100 cartons of strawberries before the store opens. For the first 3 hours the store is open,

the store sells 10 cartons per hour. Over the next 2 hours, no cartons of strawberries are sold. The store then restocks 10 cartons each hour for the next 2 hours. In the final hour that the store is open, 20 cartons are sold. Graph the function.
Mathematics
2 answers:
ehidna [41]3 years ago
6 0

Answer:

80 - 30(first hour )=50

50-0(2nd hour)=50

50-20=30

30-20=10

10 Is THE ANSWER

oksian1 [2.3K]3 years ago
5 0
100-30= 70
70 + 10 + 10 = 90
90 - 20= 70
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yulyashka [42]
3/8 would be the answer
6 0
3 years ago
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Please help with my last question.
Bas_tet [7]

Answer:

x = 8.3

y = 20.3

Step-by-step explanation:

21-\frac{2}{3} = 20\frac{1}{3} or 20.3

9-\frac{2}{3} = 8\frac{1}{3} or 8.3

6 0
3 years ago
A scale drawing of an automobile has a scale of 1 in.
Paul [167]
The correct question in the attached figure

we know that
the scale is 1 in (scale drawing)= (1/2) foot (actual)-----> 1/(1/2)=2 in/ft
[scale]=[scale drawing]/[actual]
then
[scale drawing]=[scale]*[actual]
therefore
for  <span>actual width of the car  8 ft
</span>[scale drawing]=[2 in/ft]*[8 ft]=16 in
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the answer is 16 in
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5 0
3 years ago
PLEASE HELP!!! BRAINLIEST!!!
Rashid [163]
Melissa is standing 40 ft from a tree, so m = 40 is base of the triangle.
angle of elevation (aoe) = 50°
The tree's height (h) is the side opposite the aoe (50°), therefore in trigonometry tangent 50 = opposite / adjacent. The side adjacent to that angle (50°) is the base (m). Therefore:
tan50 = h/m
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3 0
4 years ago
Suppose that ABCD is a trapezoid, with AB parallel to CD, and diagonals AC and BD intersecting at P. Explain why (a) triangles A
lora16 [44]

Answer:

A trapezoid ABCD is show below,

AB || CD

AC and BD are diagonals intersecting at P.

(a)

In Δ ABC and ABD,

Area of triangle ABC = Area of triangle ABD

Because,

Area of triangle ABC = 1/2 × Base × Height

Base = AB

Height = h, which is same for both the triangle that's why,

Area of triangle ABC = Area of triangle ABD

(b)

As we know that,

Area of triangle ABC = Area of triangle ABD

On subtracting the area of triangle ABP from both the triangles, we get

Area of triangle ABC - area of triangle ABP = Area of triangle ABD - area of triangle ABP

⇒ area of triangle BCP = area of triangle DAP

Hence, triangles BCP and DAP have the same area.

(c)

In triangle ABP and CDP,

∠ABP = ∠CDP (opposite interior angles are equal between two parallel lines)

∠APB = ∠CPD (opposite angles are equal)

∠BAP = ∠DCP (opposite interior angles are equal between two parallel lines)

Therefore,

By AAA similarity

Triangles ABP and CDP are similar.

(d)

In triangle BCP and DAP,

Only ∠BCP = ∠APD (opposite angles are equal).

Therefore,

Triangles BCP and DAP need not be similar.

8 0
3 years ago
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