What pair of integers has a -16 and a sum of -6
1 answer:
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Answer:
x^3 - 3x^2 - 3x + 9 + (-36/(x+3))
OR
x^3 - 3x^2 - 3x + 9 - (36/(x+3))
Step-by-step explanation:
First set the divisor equal to 0:
x + 3 = 0
Subtract 3 from both sides
x = -3
This is what you'll divide the dividend by in synthetic division.
Take the coefficents of each term in the dividend. Do not forget the 0 placeholders:
x^4 + 0x^3 - 12x^2 + 0x -9
Coefficents: 1. 0. -12. 0 -9.
Please see the image for the next steps.
The remainder is -36. Put the remainder over the divisor and add it to the polynomial (shown in image)
-36/(x+3)
