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2 years ago

A cheetah runs 296 feet in 4 seconds. How far could a cheetah run in 10 seconds at this rate?

Mathematics

2 answers:

melomori [17]2 years ago

4 0

Answer:

740 feet

Step-by-step explanation:

The speed of the cheetah is 74 feet per second:

speed = distance ÷ time

= 296 ÷ 4 = 74 feet per second

In 10 seconds:

distance = speed × time

= 74 × 10

= 740 feet

vlada-n [284]2 years ago

4 0

Answer:

740 Feet

Step-by-step explanation:

Given: 296 ft= 4 sec

To Find: 10 sec = $\left[?}\right]$ ft

First we need to Find How many feet are in 1 second.

To find that,

Do 296 divided by 4

So 1 second = 74 Feet.

Then 74 ft Times 10 second

Which gives you

740 Feet.

Therefore, at 10 second rate gives you 740 Feet.

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Let X = number of consumer's who recognize the brand.

The probability of the random variable X is, P (X) = p = 0.40.

A random sample of size, n = 6 consumers are selected.

The random variable X follows a Binomial distribution with parameters n and p.

The probability mass function of X is:

$P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...$

(a)

Compute the value of P (X = 5) as follows:

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Thus, the probability that exactly 5 of the 6 consumers recognize the brand name is 0.0369.

(b)

Compute the value of P (X = 6) as follows:

$P(X=6)={6\choose 6}0.40^{6}(1-0.40)^{6-6}\\=1\times 0.004096\times1\\=0.004096\\\approx0.0041$

Thus, the probability that all of the selected consumers recognize the brand name is 0.0041.

(c)

Compute the value of P (X ≥ 5) as follows:

P (X ≥ 5) = P (X = 5) + P (X = 6)

= 0.0369 + 0.0041

= 0.041

Thus, the probability that at least 5 of the selected consumers recognize the brand name is 0.041.

(d)

An event is considered unusual if the probability of its occurrence is less than 0.05.

The probability of 5 customers recognizing the brand name is 0.0369.

This probability value is less than 0.05.

Thus, the events of 5 customers recognizing the brand name is unusual.

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