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vovangra [49]
3 years ago
14

A number b is greater than or equal to 4 and at most 13

Mathematics
1 answer:
oksano4ka [1.4K]3 years ago
7 0

Answer:

Step-by-step explanation:

b is greater than or equal to 4:   4 ≤  b

and at most 13  : b ≤ 13

4 ≤ b ≤ 13

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The Garcia family is driving from San Diego, California, to Bar Harbor, Maine. In 5 days, they have traveled 2,045 miles. At thi
zysi [14]

Answer: 8

Step-by-step explanation: Well you first do 2045 divided by 5 which is 409 and then you have to do 3272 divided by 409 and you would get 8. I hope this helps!

5 0
3 years ago
When Judy worked 4 hours and Ben worked 1 hour, their combined pay was $75. When Judy worked 2 hours and Ben worked 6 hours, the
arsen [322]

Answer:

$15

Step-by-step explanation:

let the hourly rate of pay for Ben  = B

let the hourly rate of pay for Judy  = J

Judy worked 4 hours and Ben worked 1 hour, their combined pay was $75;

              4J + B = 75 ----- i

Judy worked 2 hours and Ben worked 6 hours, their combined pay was $120

               2J + 6B  = 120 --- ii

Now, we should solve the expression;

   Multiply equation ii by 2 and equation i by 1;

 

            4J + B = 75 ----- i    x 1  ;    4J + B  = 75          -- iii

            2J + 6B  = 120 --- ii  x 2 ;   4J + 12B  = 240    ---iv

Now,

 equation iv - iii;

                   11B  = 165

                      B  = $15

So, solving for J;

          4J + B = 75

         4J + 15  = 75

          4J  = 75 - 15  = 60

          J  = $15

3 0
3 years ago
5 x + 5 = -5 <br>what is x?​
romanna [79]

Answer:

x=-2

Step-by-step explanation:

6 0
3 years ago
What is 69/8 as mixed number?
Dafna1 [17]
There you go
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5 0
3 years ago
The computers of six faculty members in a certain department are to be replaced. Two of the faculty members have selected laptop
Anettt [7]

Answer:

a. \frac{1}{15}

b. \frac{2}{5}

c. \frac{14}{15}

d. \frac{8}{15}

Step-by-step explanation:

Given that there are two laptop machines and four desktop machines.

On a day, 2 computers to be set up.

To find:

a. probability that both selected setups are for laptop computers?

b. probability that both selected setups are desktop machines?

c. probability that at least one selected setup is for a desktop computer?

d. probability that at least one computer of each type is chosen for setup?

Solution:

Formula for probability of an event E can be observed as:

P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}

a. Favorable cases for Both the laptops to be selected = _2C_2 = 1

Total number of cases = 15

Required probability is \frac{1}{15}.

b. Favorable cases for both the desktop machines selected = _4C_2=6

Total number of cases = 15

Required probability is \frac{6}{15} = \frac{2}{5}.

c. At least one desktop:

Two cases:

1. 1 desktop and 1 laptop:

Favorable cases = _2C_1\times _4C_1 = 8

2. Both desktop:

Favorable cases = _4C_2=6

Total number of favorable cases = 8 + 6 = 14

Required probability is \frac{14}{15}.

d. 1 desktop and 1 laptop:

Favorable cases = _2C_1\times _4C_1 = 8

Total number of cases = 15

Required probability is \frac{8}{15}.

8 0
3 years ago
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