Answer:
We have to prove Δ ABO ≅ Δ CDO or, Δ DAO ≅ Δ BCO.
Step-by-step explanation:
Let us assume that ABCD is a parallelogram having diagonals AC and BD.
We have to prove that in a parallelogram the diagonals bisect each other.
Assume that the diagonals of ABCD i.e. AC and BD intersect at point O.
Therefore, to prove that the diagonals AC and BD bisect each other, we have to first prove that Δ ABO and Δ CDO are congruent or Δ DAO and Δ BCO are congruent.
In symbol, we have to prove Δ ABO ≅ Δ CDO or, Δ DAO ≅ Δ BCO. (Answer)
Not sure but I think it’s B
Answer:
Step-by-step explanation:
One angle is greater than 90°: Obtuse triangle
Two sides are the same length: Isosceles triangle
Answer:
<em>X</em> = 27 13/30
Step-by-step explanation:
First you need to find the least common denominator of 5 and 6 to get 30 so it is 25 5/30 + 7 12/30 + <em>x</em> = 60. From there you add the two together to get 32 17/30 + <em>x</em> = 60. Subtract 32 17/30 from both sides of the equation to get the value of <em>x</em> which comes out to 27 13/30.
