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Xelga [282]
3 years ago
6

You spin a spinner with 4 sections 1 yellow (y) , 1 purple (p) 1 red (r) and 1 blue (b) which is the sample space for one spin o

f this spinner
Mathematics
2 answers:
Ymorist [56]3 years ago
4 0

Answer:  The required sample space s is give by S = {Y, P, R, B}.

Step-by-step explanation:  Given that we spin a spinner with 4 sections, out of which one is yellow, one is purple, one is red and one is blue.

We are to write the sample space for one spin of the spinner.

The yellow section is represented by Y, purple section by P, red section by R and blue section by B.

Sine the spinner is spin once, so the possible outcomes  are one Y, one P, one R and one B.

Thus, the required sample space s is give by

S = {Y, P, R, B}.

Ira Lisetskai [31]3 years ago
3 0

Answer:

<h2>{Y,P,R,B}</h2>

Step-by-step explanation:

apex said it was right

<3

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An account earns simple interest.<br> $1675 at 4.6% for 4 years
Paul [167]

Answer:

$308.20

Step-by-step explanation:

The simple interest formula i = p·r·t applies here:

($1675)(0.046)(4) = $308.20

5 0
3 years ago
Five hundred teenagers were sampled at random about their favorite movie genre. The results are listed in the table below. Out o
MaRussiya [10]

Answer:

924 teenagers

Step-by-step explanation:

154 / 500 ×3000

= 924

Since 154 teenagers out of 500 prefer action movies, you'll just divide them by their total number 500 multiplied by the other total number 3000 to get the others who prefer action movies.

trying the others too

sci- fi

116 / 500 × 3000

= 696

romance

109 / 500 × 3000

= 654

comedy

78 / 500 × 3000

= 468

drama

43 / 500 × 3000

= 258

putting all of them together should give u ur total number

924 + 696+ 654 + 468 +258

= 3000

5 0
2 years ago
6. Sketch the region enclosed by the graphs of x =0, 6y-5x=0 and x+3y=21. Find the area
kow [346]
We can see that revolving the region formed by intersecting 3 lines, we will get 2 cones that are connected their bases.
Volume of the cone V=1/3 *πr²*h

1) small cone has r=5, and h=5
Volume small cone V1= 1/3 *π*5²*5 = 5³/3 *π
2) large cone has r=5, and h=21-6=15, h=15
Volume large cone V2= 1/3 *π*5²*15 = 5³*π
3) whole volume
5³/3 *π + 5³*π=5³π(1/3+1)=((5³*4)/3)π=(500/3)π≈166.7π≈523.6

Area
we see 2 right triangles,
Area of the triangle=1/2*b*h, where b -base, h -height
1) small one, b=5, h=5
A1=(1/2)*5*5=25/2
2)large one, b=5, h=15
A2=(1/2)*5*15=75/2
3) whole area=A1+A2=25/2+75/2=100/2=50

3 0
3 years ago
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Which is the answer of the following question
fgiga [73]

Answer:

<u>B) 25.12 cm</u>

Step-by-step explanation:

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3 0
1 year ago
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