1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ollegr [7]
3 years ago
15

Simplify Expression-

Mathematics
1 answer:
kumpel [21]3 years ago
5 0
In all these expressions you have a power of a power. 
You can solve them simply multiplying the exponents.
Remember that any quantity raised to the zero is equal to 1.
.
11) (n^4)^8 = n^(4×8) = n^32

13) (q^10)^10 = q^(10×10) = q^100

15) (x^3)^-5 = x^[3×(-5)] = x^(-15)

17) (z^8)^0z^5 = z^(8×0) z^5 = z^0 z^5 = 1×z^5 = z^5

<span> 19) (c^3)^5(d^3)^0 = c^(3</span>×5) d^(3×0) = c^15 d^0 = c^15×1 = c^15
You might be interested in
The county fair charges $1.25 per ticket for the rides. Spencer bought 17 tickets for the rides and spent a total of $30.75 at t
lara [203]

Answer:

y = 17x + 9.5

Step-by-step explanation:

17 * 1.25 = 21.25    therefore 30.75 - 21.25 = 9.5  = $9.50 admission   therefore y = 17x + 9.5

8 0
2 years ago
Help plzz i will give you brianliest Which best describes the graph of the function f(x) = 3(1.8)^x A) The graph passes through
DanielleElmas [232]

Answer:

Step-by-step explanation:

Start with why C isn't the answer.

y = 1.8^0 . The power is zero. Anything to the zero power (anything except 0 to the 0 power) is 1. So 1.8^0 is 1 not something else. C assumes that somehow 0,1.8 turns into 1.8. It does not. The second part is also wrong but you don't need it. However here it is.

x = 0        y = 3

x = 1         y = 3 * 1.8 = 5.4

x = 2        y = 3 * 1.8^2 = 3*3.24 = 9.72

You should be able to see that if you multiply 5.4 by 3, you don't get 9.72

C just does not work.

=======

The actual answer is A. That's exactly what the graph does. If you multiply 5.4 * 1.8 you should get 9.72. Just for completeness, I've included the graph.

6 0
3 years ago
HELP NEEDED PLEASE!
Setler [38]

Answer:

54

Step-by-step explanation:

\frac{4}{3} \pi r^{3} =12\pi \\r=\sqrt[3]{9} \\surface area 4\pi r^{2} = 4\pi (\sqrt[3]{9} )^2=54.372 (3dp)

4 0
3 years ago
Tripp and Rico are two dogs. Tripp weighs exactly 35 pounds more than Rico. Together, they weigh exactly 49 pounds. How much doe
babymother [125]
Call the weights of the two dogs t and r.

We know that Tripp weights 35lbs more than Rico, or:
t=r+35

We also know that the total weight of both dogs is 49lbs.:
t+r=49

Now, by substitution:
(r+35)+r=49
2r+35=49
2r+35-35=49-35
2r=14
r=\frac{14}{2}
r=7
Rico weighs 7lbs.

Then:
t=r+35
t=7+35
t=42
Tripp weighs 42lbs.

To check our work:
t+r=49
42+7=49
49=49  CHECK!
5 0
3 years ago
there are 5 pounds of apples in one bag make a table to show how many pounds of apples are in 6 bags. how do you know your answe
Dmitrij [34]
You can make a table like this:


If 1 bag=5 pounds
Then 6 bags must equal six times the weight of the first bag
5 times 6=30
Your answer is reasonable because 5+5+5+5+5+5=30

a.k.a
=5 =30


3 0
3 years ago
Read 2 more answers
Other questions:
  • If 80 percent is 72 marks what is full marks
    11·1 answer
  • I need help plzzzz, I’m really stupid
    14·1 answer
  • One number is times a first number. A third number is 100 more than the first number. If the sum of the three numbers is ​, find
    12·1 answer
  • PLEASE JUST CHECK IT OUT AND TRY YOUR BEST TO ANSWER. I WILL DEFINITELY AWARD BRAINLIEST :)
    15·1 answer
  • Which problems result in a positive number? Choose all answers that are correct. A. –4.6 • 1.6 B. –10 • (–5.2) C. 8.4 ÷ 2 D.
    13·1 answer
  • 12(6-2)-1.5<br><br>4(125÷5)-3+6
    6·1 answer
  • 2) A ray is a geometric figure that consist of
    10·1 answer
  • Compare and contrast Converse and Inverse. Explain.
    9·1 answer
  • If the sine of angle a is 15/17 what is the cosine of angle a
    9·1 answer
  • CAN SOMEONE HELP ME WITH<br> 5x-5=9(x-5)
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!