Answer:
a, b, and c are the correct answers.
Answer:
y = -5x - 1
Step-by-step explanation:
Let the equation of a line parallel to the given line is,
y - y' = m(x - x')
Where m = slope of the line
And line passes through (x', y')
Equation of a line has been given as,
5x + y = 4
y = -5x + 4
Slope of this line = -5
By the property of parallel lines "slope of the parallel lines are same",
m = -5
Parallel line passing through (-1, 4) and slope 'm' = -5 will be,
y - 4 = -5(x + 1)
y - 4 = -5x - 5
y = -5x - 5 + 4
y = -5x - 1
Therefore, equation of the parallel line will be,
y = -5x - 1
<span><u>Answer </u>
x = 30</span>°<span> or x = (360 – 30) = 330</span>°<span> for value of (0≤x≥360)
<u>Explanation
</u>
The first step is to find the anti-cosine of √3/2.
cos^(-1)〖√3/2〗=30°
So, x=30°
The values of x can be many so a limit has to be given. For one complete cycle, the values of x would be.
Since cosx is positive the value of x must have been in the first quadrant and the 4th quadrant.
So, x = 30</span>°<span> or x = (360 – 30) = 330</span>°<span>
</span>
Answer:
I guess the answer is c.... I guess it must be c