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victus00 [196]
2 years ago
9

Yumiko solved |x|>5 by solving x>-5 and x<5. explain the error yumiko made

Mathematics
1 answer:
Whitepunk [10]2 years ago
3 0

Answer:

switched signs around

Step-by-step explanation:

I believe that s/he switched the signs around so

|x|>5 is solved by x<-5 and x>5

but I'm not quite sure, sorry

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3³ - (4)(2) find da value or die mwaha
eduard

your answer will be 19

6 0
3 years ago
Is 3/7 bigger then 3/5
taurus [48]

Answer:

No they are equivalent

Step-by-step explanation:

3/7 =21/35

3/5=21/35

4 0
3 years ago
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How do you multiply fractions by whole numbers?
umka21 [38]
Rewrite the whole number as a fraction. To rewrite a whole number as a fraction, simply place the whole number over 1. ...Multiply the numerators of the two fractions. ...Multiply the denominators of the two fractions. ...Simplify.
4 0
3 years ago
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HELP ASAP PLEASEEEEEEEEEE
Andrew [12]

Given the recursive formula, each terms is five time the previous one.

This means that:

  • f(6) is 5 times f(5), which means f(6)=5f(5)
  • in turn, f(5) is 5 times f(4), so we have f(5)=5f(4). This means that f(6)=5f(5)=5\cdot 5f(4) = 25f(4)
  • Finally, f(4)=5f(3) So, substituting this back gives

f(6)=25f(4)=25\cdot 5f(3)=125f(3)

In general, since you have f(n)=5f(n-1), each time you compute a new term you multiply by a factor of 5, so if m=n+k, you have

f(m)=5^kf(n)

4 0
3 years ago
Which expression is equivalent to the following complex fraction?
user100 [1]

The equivalent expression of (1 + \frac{1}{y}) \div (1-\frac 1y) is \frac{y + 1}{y-1}

<h3>How to determine the equivalent fraction?</h3>

The fraction is given as:

(1 + \frac{1}{y}) \div (1-\frac 1y)

Take the LCM

\frac{y + 1}{y} \div \frac{y-1}y

Express as products

\frac{y + 1}{y} \times \frac{y}{y-1}

Evaluate the product

\frac{y + 1}{y-1}

Hence, the equivalent expression of (1 + \frac{1}{y}) \div (1-\frac 1y) is \frac{y + 1}{y-1}

Read more about equivalent expression at:

brainly.com/question/24734894

#SPJ1

4 0
2 years ago
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