Answer:
Step-by-step explanation: I Can Tell You The First One Is Correct And I Believe The Second Was Is Too.
Like all problems that involve images within the question, we should definitely try to draw this out. In the picture above, I have done this.
Now, we can see that this is just a simple proportion problem. For every 2.5 cm of height of the flower, we are 2 cm from the opening, or aperture. For every 20 cm of height, how far are we? We can set up the problem like this:
20 ............2.5
-------- = ---------
...x ............. 2
where x is the unknown distance to the aperture from the flower. Now, we just need to get x by itself. A typical way of solving something like this is by doing "butterfly multiplication" which is really just a shortcut haha. Anyway, I can rewrite that equation ^ as:
20×2 = 2.5 × x
Then, to solve for x, we would divide both sides by 2.5. (If you don't know why that is, please let me know and I'll elaborate).
We would then have:
20×2
------- = x
2.5
Which then simplifies to:
x = 16
Try using the same logic for your second question, and if you get stuck, I'd be happy to help! please let me know if any of this doesn't make sense. :)
Answer:
y = 5.5
Step-by-step explanation:
y = 22 * 0.5^2
=> 22* 0.25
=> 5.5
Hope this helps! :3
plz mark as brainliest!
The answer
<span>the true answer is A) 4x^2+52x+165=320; x = 2.5
proof:
since </span><span>they want to limit its area to 320 in^2
x must be equal 2.5, because </span>4.(2.5)^2+52(2.5)+165= 25+130+165=320;
the main rule of the area of a triangle is
A= (base x height )/2
let be b the base and h the height
so h=20- 6b
so 50= b x( 20-6b) /2, implies 100/b = 20 - 6b
if b=x, we have 100= 20x -6x² this is equivalent to 6x² - 20x = -100
so the answer is
<span>D) None of the choices are correct.
</span>
<span>the largest dimensions that can be used for the fountain are
</span>
<span>B) x^2+8x+16=800
C) x^2+16=800
</span>
proof
x^2+8x+16=x^2+8x+4², 4² is the area of the square fountain, and x^2+8x should be the remaining of the area, t<span>he total space that the fountain and sidewalk can use is 800, it is less than 800 ft^2.
</span>Use the same method for. x^2+16=800