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Ivenika [448]
4 years ago
13

Find three consecutive integers whose products is 85 larger than the cube of the smallest integer

Mathematics
1 answer:
Yakvenalex [24]4 years ago
5 0

Let the numbers be x, x + 1 and x + 2.

From the information given:-

x(x + 1)(x + 2) = x^3 + 85    

Solving for x:-

x(x^2 + 3x + 2) = x^3 + 85

x^3 + 3x^2 + 2x = x^3 + 85

3x^2 + 2x - 85 = 0

3x^2 - 15x + 17x - 85 = 0

3x(x - 5) + 17(x - 5) = 0

(3x + 17)(x - 5) = 0

x = -17/3 ,  5

We take x = 5 because x is an integer.

Answer:- the 3 integers  are  5, 6 and 7.



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