Answer:
185/9
Step-by-step explanation:
Answer:
4.1 should be the answer ?
We can substitute<span> y in the second equation with the first equation since y = y. The solution of the linear system is (1, 6). You can use the </span>substitution<span> method even if both equations of the linear system are in standard form</span>
This question is incomplete
Complete Question
The body of 154-pound person contains approximately 2 x 10^-1 milligrams of gold and 6 x 10^1 milligrams of aluminum.
Based on this information, the number of milligrams of aluminum in the body is how many times the number of milligrams of gold in the body?
Answer:
300 times
Step-by-step explanation:
From the above question, we are told:
The body of 154-pound person contains approximately 2 x 10^-1 milligrams of gold and 6 x 10^1 milligrams of aluminum.
We create a proportion
2 × 10^-1 mg of gold : 6 × 10^1 mg of aluminum
= 0.2 mg of gold : 60 mg of aluminum
Therefore, the number of milligrams of aluminum in the body is how many times the number of milligrams of gold in the body is calculated as:
60mg ÷ 0.2 mg
= 300
Therefore, the number of milligrams of aluminum in the body is 300 times the number of milligrams of gold in the body