I think that the answer is 3x/2yz^3 because I did [(27x^2y^4/16yz^4)*(8z/9xy^4)].
Answer:
A
Step-by-step explanation:
for the relation to be a function then each value of x in the domain must map to exactly one unique value of y in the range
this is the case for A
in B : 3 → 2 and 3 → 8 ← not a function
in C : - 2 → 5 and - 2 → 7 ← not a function
in D : 2 → 2 and 2 → 3 and 3 → 3 and 3 → 2 ← not a function
Answer:
Trinomial
Step-by-step explanation:
Because it has 3 terms.
Find a common denominator so, 3/6 plus 4/6 = 7/6
The idea is to find a linear combination a_1(5, -6) + a_2(-2, -2) = (-6, 2)
It boils down to a system of equations:
Take the augmented matrix:
<span>[<span><span>5<span>−6</span></span><span><span>−2</span><span>−2</span></span><span><span>−6</span>2</span></span>]</span>
Reduced form:
<span>[<span><span>10</span><span>01</span><span><span>−<span>811</span></span><span>1311</span></span></span>]</span>
-(8/11)*(5, -6) + (13/11)*(-2, -2) = (-6, 2)
