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2 years ago

Which relation is a function? PLEASE HELP

Mathematics

2 answers:

olganol [36]2 years ago

6 0

Answer is A I did this

Georgia [21]2 years ago

4 0

Answer:

Step-by-step explanation:

for the relation to be a function then each value of x in the domain must map to exactly one unique value of y in the range

this is the case for A

in B : 3 → 2 and 3 → 8 ← not a function

in C : - 2 → 5 and - 2 → 7 ← not a function

in D : 2 → 2 and 2 → 3 and 3 → 3 and 3 → 2 ← not a function

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Step-by-step explanation:

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Answer:

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1 + 2.828i
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Explanation:

Complex numbers have the general form a + bi, where a is the real part and b is the imaginary part.

Since, the numbers are neither purely imaginary nor purely real a ≠ 0 and b ≠ 0.

The absolute value of a complex number is its distance to the origin (0,0), so you use Pythagorean theorem to calculate the absolute value. Calling it |C|, that is:

$|C| = \sqrt{a^2+b^2}$

Then, the work consists in finding pairs (a,b) for which:

$\sqrt{a^2+b^2}=3$

You can do it by setting any arbitrary value less than 3 to a or b and solving for the other:

$\sqrt{a^2+b^2}=3\\ \\ a^2+b^2=3^2\\ \\ a^2=9-b^2\\ \\ a=\sqrt{9-b^2}$

I will use b =0.5, b = 1, b = 1.5, b = 2

$b=0.5;a=\sqrt{9-0.5^2}=2.958\\ \\b=1;a=\sqrt{9-1^2}=2.828\\ \\b=1.5;a=\sqrt{9-1.5^2}=2.598\\ \\b=2;a=\sqrt{9-2^2}=2.236$

Then, four distinct complex numbers that have an absolute value of 3 are:

0.5 + 2.985i
1 + 2.828i
1.5 + 2.598i
2 + 2.236i

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