By inspection, it's clear that the sequence must converge to

because

when

is arbitrarily large.
Now, for the limit as

to be equal to

is to say that for any

, there exists some

such that whenever

, it follows that

From this inequality, we get




As we're considering

, we can omit the first inequality.
We can then see that choosing

will guarantee the condition for the limit to exist. We take the ceiling (least integer larger than the given bound) just so that

.
If we write y=f(x)=(x-h)²+k, then y-k=(x-h)². This is vertex form where the vertex is (h,k)=(3,3) so h and k are both 3. We can see this if we put x=3 in the shifted function. This is a minimum point for the function because for every other x f(x) is greater then 3. The minimum point is the vertex.
Answer:
ABCD
Step-by-step explanation:
so first you use glue and then paint and then contact solution
Yes, it would be correct because a triangle has to add up to 180 degrees when all the angles are added up
A) Explanation:
95 + 10 + 75 = 180
B) A triangle will always add up to 180.
If you have a TI-83 Plus calculator . You can go to 2nd X^-1 and use the matrices