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Radda [10]
3 years ago
9

27x^2y^4÷16yz^4×8z÷9xy^4

Mathematics
1 answer:
arlik [135]3 years ago
8 0

I think that the answer is 3x/2yz^3 because I did [(27x^2y^4/16yz^4)*(8z/9xy^4)].

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How do you write 100, in an exponential form
Allushta [10]

1. 10^2

2. 10^5

3. 10^4

Hope this helped!

Nate

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3 years ago
A rectangular flower bed is five feet longer than it is wide. its area is eighty-four square feet.
777dan777 [17]
Lets say w is the width of the flower bed. We can make an equation to find the area.
The length of the of the flower bed is (w+5) and the width is w.
To find the area we need to multiply the length(w+5) by the width(w) and set it equal to 84,
(w+5)(w)=84
w^2 +5w=84
Using the quadratic equation you get the solutions of 7 and -12. Since 7 is positive it is our width. Our length is 7+5 or 12.
3 0
3 years ago
Solve the system of linear equations below.
alexdok [17]

Answer:

The answer is X=3, Y=2

hope this helps :)

3 0
3 years ago
Trapezoid CDEF is congruent to trapezoid TORS. If CF and DE are parallel, which pair of sides in trapezoid TQRS MUST also be par
kondaur [170]

Answer:

D

Step-by-step explanation:

TS and QR Is your answer

6 0
3 years ago
PLEASE HELP ITS EXTRA CREDIT AND I COULD REALLY USE IT !! BEING TIMED! for each of the following statements, determine if the st
bogdanovich [222]

A. True. We see this by taking the highest order term in each factor:

f(x) = -3x(x-5)^3(x+2)^2 = -3x (x^3 + \cdots) (x^2 + \cdots) = -3x^{\boxed{6}} + \cdots

B. True. Again we look at the leading term's degree and coefficient. f(x) behaves like -3x⁶ when x gets large. The degree is even, so as x goes to either ± ∞, x⁶ will make it positive, but multiplying by -3 will make it negative. So on both sides f(x) approaches -∞.

C. False. f(x) = 0 only for x=0, x = 5, and x = -2.

D. False. Part of this we know from the end behavior discussed in part B. On any closed interval, every polynomial is bounded, so that for any x in [-2, 5], f(x) cannot attain every positive real number.

E. True. x = 0 is a root, so f(0) = 0 and the graph of f(x) passes through (0, 0).

F. False. (0, 2) corresponds to x = 0 and f(x) = 2. But f(0) = 0 ≠ 2.

8 0
2 years ago
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