Round 13.897 to the nearest tenth

Parker drove a total distance of 4 and 1 over 2 miles during the months of June and July. If Parker only drove 1 over 8 of a mil

never [62]

Answer: 4 and 1 over 2 ÷ 1 over 8

Step-by-step explanation:

Given that : Total distance drove by Parker =4 and 1 over 2 miles= $4\frac{1}{2}$ miles

Distance drove by Parker each day = 1 over 8 mile= $\frac{1}{8}$ mile

To find the total number of days , we need to divide the total distance by the distance drove by him in each day.

Thus, the number of days he went driving=4 and 1 over 2 ÷ 1 over 8

5 0

2 years ago

Read 2 more answers

Which fraction is bigger 5/6 or 8/9?

dimulka [17.4K]

5/6 = 5 ÷ 6 = 0.8333

8/9 = 8 ÷ 9 = 0.8888

so 8/9 is bigger.

hope this helped, God bless!

4 0

3 years ago

Read 2 more answers

If y is 15 times x, which equation shows the relationship between x and y?

zhannawk [14.2K]

Is= equals sign
times= multiplication

So y equals 15 times x

y= 15 * x
y= 15x

ANSWER: y= 15x (bottom choice)

Hope this helps! :)

4 0

2 years ago

find the area of the trapezium whose parallel sides are 25 cm and 13 cm The Other sides of a Trapezium are 15 cm and 15 CM

Snezhnost [94]

$\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}$

Given - A trapezium ABCD with non parallel sides of measure 15 cm each ! along , the parallel sides are of measure 13 cm and 25 cm

To find - Area of trapezium

Refer the figure attached ~

In the given figure ,

AB = 25 cm

BC = AD = 15 cm

CD = 13 cm

Construction -

$draw \: CE \: \parallel \: AD \: \\ and \: CD \: \perp \: AE$

Now , we can clearly see that AECD is a parallelogram !

$\therefore$ AE = CD = 13 cm

Now ,

$AB = AE + BE \\\implies \: BE =AB - AE \\ \implies \: BE = 25 - 13 \\ \implies \: BE = 12 \: cm$

Now , In ∆ BCE ,

$semi \: perimeter \: (s) = \frac{15 + 15 + 12}{2} \\ \\ \implies \: s = \frac{42}{2} = 21 \: cm$

Now , by Heron's formula

$area \: of \: \triangle \: BCE = \sqrt{s(s - a)(s - b)(s - c)} \\ \implies \sqrt{21(21 - 15)(21 - 15)(21 - 12)} \\ \implies \: 21 \times 6 \times 6 \times 9 \\ \implies \: 12 \sqrt{21} \: cm {}^{2}$

Also ,

$area \: of \: \triangle \: = \frac{1}{2} \times base \times height \\ \\\implies 18 \sqrt{21} = \: \frac{1}{\cancel2} \times \cancel12 \times height \\ \\ \implies \: 18 \sqrt{21} = 6 \times height \\ \\ \implies \: height = \frac{\cancel{18} \sqrt{21} }{ \cancel 6} \\ \\ \implies \: height = 3 \sqrt{21} \: cm {}^{2}$

Since we've obtained the height now , we can easily find out the area of trapezium !

$Area \: of \: trapezium = \frac{1}{2} \times(sum \: of \:parallel \: sides) \times height \\ \\ \implies \: \frac{1}{2} \times (25 + 13) \times 3 \sqrt{21} \\ \\ \implies \: \frac{1}{\cancel2} \times \cancel{38 }\times 3 \sqrt{21} \\ \\ \implies \: 19 \times 3 \sqrt{21} \: cm {}^{2} \\ \\ \implies \: 57 \sqrt{21} \: cm {}^{2}$

hope helpful :D

6 0

1 year ago

The ratio of powder to water is 1:8 if there are 32 cups of powder how many cups of water are needed

In-s [12.5K]

There are 256 cups of water needed. I hope this helped.

6 0

2 years ago