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adell [148]
3 years ago
13

Round 13.897 to the nearest tenth

Mathematics
1 answer:
ohaa [14]3 years ago
7 0

Answer: 13.900

Step-by-step explanation:

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4) Which pair of triangles is congruent by Angle - Angle- Side?
andrey2020 [161]

Answer:

1. Not equal

2. Equal but not connected

3. Equal

4. Equal

Step-by-step explanation: Sorry if not correct :(

3 0
2 years ago
Listed below are the overhead widths​ (in cm) of seals measured from photographs and the weights​ (in kg) of the seals. Construc
Anarel [89]

Answer and Step-by-step explanation: Scaterplot is a type of graphic which shows the relationship between to variables. In this question, you want to determine if there is a linear relationship between overhead widths of seals and the weights. So, the hypothesis are:

H₀: no linear correlation;

H₁: there is linear correlation;

In this hypothesis test, to reject H₀, the correlation coefficient r of the data set has to be bigger than the critical value from the table.

With α = 0.05 and n = 6, the critical value is 0.811.

The linear correlation is calculated as:

r = n∑xy - ∑x.∑y / √[n∑x² - (∑x)²] [n∑y² - (∑y)²]

r = \frac{6.9632 - 51.1108}{\sqrt{6.439 - (51^{2} )}.6.14482 - (1108^{2} ) }

r = 0.9485

Since r is bigger than the critical value, H₀ is rejected, which means there is enough evidence to conclude that there is linear correlation between overhead widths and the weights.

In the attachments is the scaterplot of the measurements, also showing the relationship.

5 0
3 years ago
What is the square root of 147?
olga nikolaevna [1]
The square root of 147 when rounded to the nearest tenth is about 12.1
7 0
3 years ago
The following piecewise function gives the tax owed, T(x), by a single taxpayer on a taxable income of x dollars.

T(x) = (i) De
Luda [366]

(i) To show that a piecewise function is continuous at a point, we need to show that the left hand and right hand limit "agree" with each other. In other words, we want:

\lim_{x\to 6061^-} T(x) = \lim_{x \to 6061^+} T(x)

Now, since we're given the constraints and the equation of each constraint, we notice that 6061^+ is a number that is slightly bigger than 6061. So we use the second equation. Do you see why?

In much the same way, 6061^- is a number that is slightly smaller than 6061. So we use the first equation. Again, do you see why? (Hint: look at the conditions on x for each equation).

So finally, computing each limit means just "plugging" 6061 into their respective equations. That is:

\lim_{x \to 6061^-} T(x) = 0.10\times 6061 = 606.1

\lim_{x \to 6061^+} T(x) = 606.1 + 0.18(6061 - 6061) = 606.1

Since your limits match, we say that, at the point x = 6061, T(x) IS continuous.

(ii) Repeat the process above with x = 32473.

(iii) Find a point of discontinuity just means your right hand and left hand limits do not match -- I'm not an economist, so I may not be of much help with the latter part of the question!

6 0
3 years ago
Read 2 more answers
yael used to have a square garage with 292ft^2 of floor space.she recently built an addition to it. The garage is still a​ squar
Arturiano [62]

Answer: 19

If the floor space of the garage is increased by 50%, that means its area is increased by that amount

So we have 228 + .50(228) = 228 + 114 = 342 ft²

Since the original garage is square-shaped with an area of 228 ft², then we can find the length of each side. If we let x = the side length, then we have:

x² = 228

x = 15.1 ft

Assuming that the garage will remain square-shaped with sides of uniform dimensions, then we can label each side of the expanded garage as 15 + y. We need to solve for y. Again, we use the area formula. Remember that the expanded garage will have an area of 342 ft², we now have:

(y + 15)² = 342

y² + 30y + 225 = 342

y² + 30y - 117 = 0

This can be solved using the Quadratic Formula. Remember that dimensions must always be positive. Once you determine y, then you will know what the length will be of the expanded garage

8 0
2 years ago
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