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3 years ago

Fill in the blank with the appropriate angle:

Mathematics

1 answer:

Gre4nikov [31]3 years ago

3 0

Answer:

Step-by-step explanation:

Same side interior angles refers to the pair of angles which are inside the two "parallel" lines and at the same side of the transversal line.

Notice that angles BGH and DHG are same side interior angles. Similarly, angles AGH and CHG are also same side interior angles.

Therefore, the right answer is ∠DHG.

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Through which two points could a line of rotation be placed so that the base of the resulting cylinder will have a radius of 5 c

vagabundo [1.1K]

Answer:

G and H

Step-by-step explanation:

just took the test in edg.

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3 years ago

Read 2 more answers

If 1 foot 12 inches, which expression can be used to find the

Liono4ka [1.6K]

B is the right awnser

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3 years ago

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The box plots below show student grades on the most recent exam compared to overall grades in the class: two box plots shown. Th

finlep [7]

Question:

The box plots below show student grades on the most recent exam compared to overall grades in the class: two box plots shown. The top one is labeled Class. Minimum at 70, Q1 at 74, median at 83, Q3 at 92, maximum at 100. The bottom box plot is labeled Exam. Minimum at 60, Q1 at 81, median at 87, Q3 at 91, maximum at 95. Which of the following best describes the information about the medians? (1 point) Group of answer choices

•The exam outlier at 60 makes the IQR narrower and the median higher.

•The class data is more evenly spread, which pulls its median down.

•The class median is lower than the exam median.

•The class Q3 is higher than the exam Q3.

Answer:

•The class Q3 is higher than the exam Q3.

Step-by-step explanation:

In the question we have two box plots

a) Box plots for class is given as

Minimum at 70, Q1 at 74, median at 83, Q3 at 92,

b) Box plots for exam is given as Minimum at 60, Q1 at 81, median at 87, Q3 at 91, maximum at 95.

When we compare the median of the class which is 83 and the median of the exam plots 87, we can see that the median of the exam is higher than the median of the class, hence the option

"•The class median is lower than the exam median". is wrong.

From the options given, the only correct option which best describes the information about the medians is

"•The class Q3 is higher than the exam Q3".

This is because when we compare the Q3 of the class which is 92 to the Q3 of the box which is 91 , we can see that the class Q3 is higher than the box Q3 hence the option is correct.

8 0

3 years ago

What is the value of 3 to the power 2 over 3 to the power 4? A. 1 over 81 B. 1 over 27 C. 1 over 9 D. 1 over 3

rodikova [14]

One way you could solve this is to just multiply the top and bottom out so that you get 9/81, reducing it by 9/9 to get 1/9 or option C.
Another way would be to do $3^{(2-4)}$ since dividing numbers with exponents would be subtracting the bottom exponent from the top exponent, provided that the base number (in this case 3) is the same for both. For this method, you would get $3^{-2}$ , which is equal to 1/9 or .1 repeating, the same answer that you'd get with the first method.

6 0

3 years ago

Read 2 more answers

Answer this pls..................

Sindrei [870]

Answer:

so we know:

total of 20 students

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20

chemistry has a total of 14 students

1 2 3 4 5 6 7 8 9 10 11 12 13 14

8 students are in physics

1 2 3 4 5 6 7 8

3 are in all of them

1 2 3

1) underline the main 3

total of 20 students

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20

chemistry has a total of 14 students

1 2 3 4 5 6 7 8 9 10 11 12 13 14

8 students are in physics

1 2 3 4 5 6 7 8

2) lets bold the physics students, if you are in physics you have to do chem so that means 8 of the chem students also take physics.

total

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20

chemistry

1 2 3 4 5 6 7 8 9 10 11 12 13 14

physics

1 2 3 4 5 6 7 8

3) now we bring biology into the "equation"

off the bat we know 3 are definitely in Biology.

so if 4 study ONLY biology we can cross them off our list see the {}

total

1 2 3 4 5 6 7 8 {9 10 11 12} 13 14 15 16 17 18 19 20

chemistry

1 2 3 4 5 6 7 8 {9 10 11 12} 13 14

physics

1 2 3 4 5 6 7 8

biology

1 2 3 

4) so we have a total of 20 students, 3 in all of the classes (underlined), 8 in physics (bolded). If there 14 in chemistry, 4 take ONLY chemistry {}, 8 take chemistry as well (bolded), that leaves two students, so they must belong in biology. lets italicise them.

total

1 2 3 4 5 6 7 8 {9 10 11 12} 13 14 15 16 17 18 19 20

chemistry

1 2 3 4 5 6 7 8 {9 10 11 12} 13 14

physics

1 2 3 4 5 6 7 8

biology

1 2 3  13 14

5) out of our total of 20 students we know 14 of the students classes, so the remaining six must be in biology.

1 2 3 4 5 6 7 8 {9 10 11 12} 13 14 15 16 17 18 19 20

chemistry

1 2 3 4 5 6 7 8 {9 10 11 12} 13 14

physics

1 2 3 4 5 6 7 8

biology

1 2 3 13 14 15 16 17 18 19 20

6) so that was our "diagram" so now lets count how many are in chemistry and biology but NOT physics.

1 2 3 4 5 6 7 8 {9 10 11 12} 13 14 15 16 17 18 19 20

chemistry

-1 2 3 4 5 6 7 8- {9 10 11 12} 13 14

physics

-1 2 3 4 5 6 7 8-

biology

-1 2 3 -13 14 15 16 17 18 19 20

there are 14 students in chemistry and 11 in biology, 5 of them are in both classes so 14-5= 9 and 11-5= 6 9+6=16. BUT 8 of those sixteen are also in -physics- so we arent counting them, we put those students in dashes. so lets count the students out of the dashes. so twelve of them are in chemistry and biology but not physics.

7) so how many are in just biology but not the other classes? lets look at the graph.

1 2 3 4 5 6 7 8 {9 10 11 12} 13 14 15 16 17 18 19 20

chemistry

1 2 3 4 5 6 7 8 {9 10 11 12} 13 14

physics

1 2 3 4 5 6 7 8

biology

1 2 3 13 14 15 16 17 18 19 20

in the class of biology students 1 2 3 13 and 14 take other classes that leaves students 15 16 17 18 19 and 20. so 6 students take ONLY biology.

sorry its long but i hope this helps!

3 0

3 years ago