A fish tank contains 9 Goldfish and 7 Angelfish. If one fish was randomly removed from the tank what is the
1 answer:
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Answer:
246.3%
the complete question is found in the attached document
Step-by-step explanation:
1st step:
using 1936 data,
w1= 356% = 3.56(356/100) , H= 79 feet
specific gravity = 2.65
Sₓ= 100%= 1
initial void ratio(e₀)= (w1 x specific gravity)/Sₓ
=3.56 x 2.65/1 = 9.434
2nd step
using 1996 data
ΔH= 22ft
ΔH/H = Δe/(1 + e₀)
22/79 = Δe/(1+9.434)
0.278=Δe/10.434
Δe= 0.278 x 10.434
Δe= 2.905
Δe= e₀ - eₓ
eₓ= e₀-Δe
eₓ= 9.434 - 2.905
eₓ= 6.529
3rd step
calculating water content in 1996
eₓ =6.529, specific gravity= 2.65, Sₓ= 100%
W2 X 2.65 = 1 x 6.529
w2 = 6.529/2.65 = 2.463 = 246.3%
Answer:
Mean. It includes all data points.
Step-by-step explanation:
-We first need to calculate the mean, median and mode then compare our values:
#Mean:
#The median is the middlemost data point in a lsit data:
778,783,784,786,790,804,807,810,819,823
-Since our data points is an even number, the median number is calculated as:
#Mode is the data point with the highest frequency:
-Since there's no number appearing more than once, our set has no mode.
#Since our data set has no outliers and is not a skewed distribution, the mean will be the best measure as it includes all data points
Answer:
63 m
Step-by-step explanation:
We are given the following in the question:
Average speed of swimming = 45 m/min
Time = 1 minute 24 seconds
Converting time into minutes:
Formula:
Putting values, we get.
Thus, Alex swims for 63 m in 1 minute and 24 seconds.