Question 10, 4.A.27

The area of a triangle is Half the area of a rectangle with the same base and height *

Vaselesa [24]

Answer:

Always.

Step-by-step explanation:

That is the reason why when you are trying to calculate the area of a triangle you do the base x height divided by two or in half. If you printed out the triangle twice then cut it out and put the two together it would be a rectangle.

5 0

3 years ago

Read 2 more answers

Use elimination to solve each system of equations<br> 2x-y=-1<br> 3x-2y=1

mixer [17]

$2x-y=-1 \ \ \ |\times (-2) \\
3x-2y=1 \\ \\
-4x+2y=2 \\
\underline{3x-2y=1 \ \ \ \ } \\
-4x+3x=2+1 \\
-x=3 \ \ \ |\times (-1) \\
x=-3 \\ \\
2x-y=-1 \\
2 \times (-3)-y=-1 \\
-6-y=-1 \ \ \ |+6 \\
-y=5 \ \ \ |\times (-1) \\
y=-5 \\ \\
\boxed{(x,y)=(-3,-5)}$

8 0

4 years ago

Read 2 more answers

Suppose you just received a shipment of nine televisions. Three of the televisions are defective. If two televisions are randoml

Temka [501]

<h2>Answer:</h2>

a)

The probability that both televisions work is: 0.42

b)

The probability at least one of the two televisions does not work is:

0.5833

<h2>Step-by-step explanation:</h2>

There are a total of 9 televisions.

It is given that:

Three of the televisions are defective.

This means that the number of televisions which are non-defective are:

9-3=6

a)

The probability that both televisions work is calculated by:

$=\dfrac{6_C_2}{9_C_2}$

( Since 6 televisions are in working conditions and out of these 6 2 are to be selected.

and the total outcome is the selection of 2 televisions from a total of 9 televisions)

Hence, we get:

$=\dfrac{\dfrac{6!}{2!\times (6-2)!}}{\dfrac{9!}{2!\times (9-2)!}}\\\\\\=\dfrac{\dfrac{6!}{2!\times 4!}}{\dfrac{9!}{2!\times 7!}}\\\\\\=\dfrac{5}{12}\\\\\\=0.42$

b)

The probability at least one of the two televisions does not work:

Is equal to the probability that one does not work+probability both do not work.

Probability one does not work is calculated by:

$=\dfrac{3_C_1\times 6_C_1}{9_C_2}\\\\\\=\dfrac{\dfrac{3!}{1!\times (3-1)!}\times \dfrac{6!}{1!\times (6-1)!}}{\dfrac{9!}{2!\times (9-2)!}}\\\\\\=\dfrac{3\times 6}{36}\\\\\\=\dfrac{1}{2}\\\\\\=0.5$

and the probability both do not work is:

$=\dfrac{3_C_2}{9_C_2}\\\\\\=\dfrac{1}{12}\\\\\\=0.0833$

Hence, Probability that atleast does not work is:

0.5+0.0833=0.5833

4 0

4 years ago

Marcella dived 40.8 gallons of paint among 8 coontainer How much paint is in each container

erma4kov [3.2K]

5.1gallons is in each container

3 0

3 years ago

BRAINLEIST!!!! You have a credit card with a balance of $754.43 at a 13.6% APR. You have $300.00 available each month to save or

Alex

We are given
P = $754.43
r = 13.6% annual

for a.
A = 150
for b.
A = 300

First, change the interest into effective monthly
i = (1 + 0.136/12)^12 - 1
Solve for i

Next, use the general formula
A = P i ( 1 + i)^n / (1 + 1)^n - 1
Subsitute P, i, and A for a and b.
Then, solve for n for a and b.

6 0

3 years ago