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inessss [21]
2 years ago
8

63 first-graders and 21 other students attended a school assembly. What percentage of the

Mathematics
2 answers:
boyakko [2]2 years ago
4 0

Answer:

75%

Step-by-step explanation:

alexira [117]2 years ago
3 0

Answer:

75%

Step-by-step explanation:

First let's start by finding the total number of students at the assembly:

63+21=84

Then we find the percentage of the students that were first-graders.

63/84=9/12=3/4=75/100=75%

As further explanation to how this works:

We take the number of first graders over the total number of students so we can find the percentage. Then we simplify it down to 3/4. Since percentages are out of 100 we can change the fraction so it's something out of 100. We multiply the numerator and denominator by 25 (since 100/4=25) and we get 75/100 which is 75%

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Bogdan [553]

Answer:1 and 2

Step-by-step explanation:

Given

Volume needed V=220\ in.^3

For first cylinder

r=3\ in.

h=4\ in.

V=\pi r^2h

V_1=\pi (3)^2(4)

V_1=113.11\ in^3

For second cylinder

r=4\ in.

h=4\ in.

V=\pi r^2h

V_2=\pi (4)^2(4)

V_2=201.08\ in^3

For Third cylinder

r=9\ in.

h=9\ in.

V=\pi r^2h

V_3=\pi (9)^2(9)

V_3=2290.51\ in^3

For fourth cylinder

r=4\ in.

h=9\ in.

V=\pi r^2h

V_4=\pi (4)^2(9)

V_4=452.448\ in^3

So, cylinder 1 and 2 are appropriate as it is under 220\ in.^3

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2 years ago
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4 0
3 years ago
(n^3 +67² + 4n - 2)/(n + 1)
Alla [95]

Answer:

(n^3 + 4 n + 4487)/(n + 1)

Step-by-step explanation:

Simplify the following:

(n^3 + 4 n - 2 + 67^2)/(n + 1)

| | 6 | 7

× | | 6 | 7

| 4 | 6 | 9

4 | 0 | 2 | 0

4 | 4 | 8 | 9:

(n^3 + 4 n - 2 + 4489)/(n + 1)

Grouping like terms, n^3 + 4 n - 2 + 4489 = n^3 + 4 n + (4489 - 2):

(n^3 + 4 n + (4489 - 2))/(n + 1)

4489 - 2 = 4487:

Answer: (n^3 + 4 n + 4487)/(n + 1)

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3 years ago
What is..Simplify 15.8
ycow [4]

Answer:

simplify of 15.8 is 16

Step-by-step explanation:

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2 years ago
The legs of a right triangle measure 6 inches and 9 units. If theta is the angle between the 6-inch leg and the hypotenuse, sin
Alex73 [517]
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