3 times 2 is 6 times 5 is 35
20/28 = 3x / (4x + 2)
84x = 20(4x + 2)
84x - 80x = 40
4x = 40
x = 10
so the 2 lines are equal to 30 and 42
Let s represent the length of any one side of the original square. The longer side of the resulting rectangle is s + 9 and the shorter side s - 2.
The area of this rectangle is (s+9)(s-2) = 60 in^2.
This is a quadratic equation and can be solved using various methods. Let's rewrite this equation in standard form: s^2 + 7s - 18 = 60, or:
s^2 + 7s - 78 = 0. This factors as follows: (s+13)(s-6)=0, so that s = -13 and s= 6. Discard s = -13, since the side length cannot be negative. Then s = 6, and the area of the original square was 36 in^2.
Nineteen million, two hundred sixty-six thousand, four hundred twenty! :)
