Answer:
The explicit rule for this situation is
In row 12 there will be 14 pins
Step-by-step explanation:
We have an initial amount of 3 pins in the first row. Let's call the number of pins in row n.
where n is an integer and .
So
In row n + 1 there will always be a pin more than in the previous row n, then:
Then:
<em>Finally in row 12 there will be:
</em>
Answer:
11n=35
Step-by-step explanation:
First, you do 2n+9n
2n+9n+11n
11n-8=27
Next, you add 8 to each side
11n=27+8
11n=35
Answer:
b or d
Step-by-step explanation:
i know it is not a or c
The correct answer for this question is this one: "B. the quotient 5 cubed over 5 to the fourth, raised to the negative 3 power"
<span>A. 5 times the quotient 5 cubed over two-fifths, raised to the second power
B. the quotient 5 cubed over 5 to the fourth, raised to the negative 3 power
C. 5 to the negative 2 over 5 to the negative 5
E. 5 times the quotient 5 to the 5 over 5 cubed</span>