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2 years ago

PLEASE HELP ME KIND SOUL! Look at the picture below to understand everything

Mathematics

1 answer:

ruslelena [56]2 years ago

5 0

Answer:

Yes, it is 368.24, because you cannot use a digit more than once.

Step-by-step explanation:

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How can you know if this equation is true?<br><br> 1/3+1/5=2/8=1/4

Harman [31]

By finding like denominators, you can add the fractions on each side. Then, compare by cross multiplying.

6 0

2 years ago

What is the answer to the Brain Teaser below

lawyer [7]

Answer:

Step-by-step explanation:

The boots are the value of 10, since 3 equal 30. The man is the value of 5 since there are two men (10) and one boot (also 10) which made 20. The ribbon is the value of 4 since there is one man (5) and 2 ribbons (8 ) which made 13. add 10, 5 and 4 and you get 19.

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2 years ago

Read 2 more answers

What is the speed of each

elena-s [515]

the rates of change will be 210. if the change is after 8 hours than the rate of change will be 105

7 0

2 years ago

the lengths of the side of a rectangular window have the ratio 1.7 to 1 the area of the window is 2,720 sqaure inches what are d

nignag [31]

Answer:

$Lenght: 68\ in\\\\Width: 40\ in$

Step-by-step explanation:

The formula for calculate the area of a rectangle is:

$A=lw$

Where "l" is the lenght and "w" is the width.

You know that the ratio of the sides of the rectangular window is:

$1.7:1$

Then, let be $x$ the width (in inches) of the rectangular window and $1.7x$ the lenght (in inches) of the rectangular window.

Knowing that the area of the window is 2,720 square inches, you can know that:

$(1.7x)(x)=2,720$

Now you must solve for "x" in order to find the width:

$(1.7x)(x)=2,720\\\\1.7x^2=\\\\x=\sqrt{\frac{2,720}{1.7} }\\\\x=40$

Finally, the lenght is:

$1.7x=1.7(40)=68$

3 0

3 years ago

Find the mass of the triangular region with vertices (0, 0), (3, 0), and (0, 1), with density function ρ(x,y)=x2+y2.

ololo11 [35]

Since density is the ratio of mass to (in this case) area, we can find the mass of the triangular region $\mathcal T$ by computing the double integral of the density function over $\mathcal T$ :

$\mathrm{mass}=\displaystyle\iint_{\mathcal T}\rho(x,y)\,\mathrm dx\,\mathrm dy$

The boundary of $\mathcal T$ is determined by a set of lines in the $x,y$ plane. One way to describe the region $\mathcal T$ is by the set of points,

$\mathcal T=\left\{(x,y)\mid0\le x\le 3\,\land\,0\le y\le1-\dfrac x3\right\}$

So the mass is

$\mathrm{mass}=\displaystyle\int_{x=0}^{x=3}\int_{y=0}^{y=1-x/3}(x^2+y^2)\,\mathrm dy\,\mathrm dx$

$=\displaystyle\int_{x=0}^{x=3}\left(x^2y+\frac{y^3}3\right)\bigg|_{y=0}^{y=1-x/3}\,\mathrm dx$

$=\displaystyle\int_{x=0}^{x=3}\left(x^2\left(1-\frac x3\right)+\frac{\left(1-\frac x3\right)^3}3\right)\,\mathrm dx$

$=\displaystyle\frac1{81}\int_0^3(27-27x+90x^2-28x^3)\,\mathrm dx=\frac52$

6 0

2 years ago