PLEASE HELP ME KIND SOUL! Look at the picture below to understand everything

Mathematics

1 answer:

ruslelena [56]3 years ago

5 0

Answer:

Yes, it is 368.24, because you cannot use a digit more than once.

Step-by-step explanation:

You might be interested in

Divide 50 into the ratio 1:4

Alex787 [66]

The answer is 10:40
so 1:4
add it up
1+4=5

so 5 total units
$50=5 units
divide by 5
$10=1 unit

so 1:4=10:10 times 4=10:40

the answer is 10:40

7 0

3 years ago

Read 2 more answers

Given: KL || MN Prove: KM/JM = LN/JL

jeka94

Answer:

See the bolded parts below. It corresponds to the blanks we have to fill in for each step.

Step-by-step explanation:

Taking a look at the figure, we see that KL ║ MN, ( which is given, as you can see ) while MJ and NJ act each as a transversal. This is a key point that will help us.

2. For step 2, we see that ∠JKL ≅ ∠JMN, while ∠JLK ≅ ∠JNM. This is true is they are present as corresponding angles, on either transversal. We can fill in this blank with " Corresponding angles. "

3. Therefore, for this 3rd step triangles JKL and JMN will be similar by " angle angle similarity. " After all, ∠JKL ≅ ∠JMN / ∠JLK ≅ ∠JNM.

4. This step can be proved by the " Proportionality of Corresponding Parts in Similar Triangles. " As you can see, the triangles are similar - and hence their parts correspond to one another.

5. I believe you mean step 5 to be " JM = JK + KM and JN = JL + LN. " That being said this is true by the " Partition Postulate, " which states that a whole is composed of it's parts.

6. This step substituted the 5th step into the 4th step. Therefore, it can be stated as " Substitute step 5 ➡ step 4. "

7. And for this last step here you can say " Simplify further. "

4 0

4 years ago

Plot another sin function of 20% higher frequency over the same range.

Ostrovityanka [42]

Step-by-step explanation:

The frequency of sine function is given by the number of periods in a given range. For example:

Frequency for $sin(x)$ is 1 in the interval $[0,2\pi]$ .

This means that, if we want another sine function with frequency 20% higher, we need that function to have a frequency of 1.2 in the interval $[0,2\pi]$ .

To be easier to see we will consider interval $[0,10\pi]$ instead of $[0,2\pi]$ . In this interval $sin(x)$ has 5 periods, therefore our new sine function should have 6 periods.

Finally, as we can see in the graph, the function $sin(\frac{6}{5}x )$ (in blue) has a frequency 20% higher than $sin(x)$ (in red). This can be easily seen counting the number of periods between 0 and $10\pi$ for both functions. 5 for $sin(x)$ and 6 for $sin(\frac{6}{5} x)$ .