I’ll give brainliest please help
1 answer:
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<h3>A.</h3>
See below for a graph
<h3>B.</h3>The inverse of a function appears on a graph as the reflection of the function across the line y=x. This is because the inverse relation is effectively the same relation with the variables x and y swapped. Here, the graphs of f(x) and g(x) are mirror images of each other across the line y=x, so we can see they are inverse functions.
The same technology allows us to graph y=f(g(x)) and y=g(f(x)). Both are graphs of y=x, as expected.
<u>Given</u>:
Given that the graph OACE.
The coordinates of the vertices OACE are O(0,0), A(2m, 2n), C(2p, 2r) and E(2t, 0)
We need to determine the midpoint of EC.
<u>Midpoint of EC:</u>
The midpoint of EC can be determined using the formula,
Substituting the coordinates E(2t,0) and C(2p, 2r), we get;
Simplifying, we get;
Dividing, we get;
Thus, the midpoint of EC is (t + p, r)
Hence, Option A is the correct answer.