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notsponge [240]
3 years ago
6

Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).

Mathematics
1 answer:
nataly862011 [7]3 years ago
7 0

ggggggghhhhhhhjjjjjjjsjsj

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3x+4/21 = x/3 x=-3 x=-1 x=3 or x=1
Irina18 [472]

Answer:

Step-by-step explanation:

false

false

true

6 0
3 years ago
Surface area of solid cuboid 8cm 6cm 2cm
strojnjashka [21]

Answer:

152 \text{cm}^2

Step-by-step explanation:

We know that the total surface area of a cuboid is the sum of the  surface area of all six of its faces.

We also know that each opposing side has the same surface area. Thus the total surface area is equal to:

2*(8*6+8*2+6*2)\\\\=2*(48+16+12)\\=2*76\\=152(\text{cm}^2)

6 0
3 years ago
AC and DB are chords that intersect at point H.
valentinak56 [21]

Answer:

16 units

Step-by-step explanation:

see the attached figure to better understand the problem

Applying  the Intersecting Chords Theorem

we have that

AH*HC=DH*HB

substitute the given values

(20-x)(x)=(x+4)(12-x)

20x-x^2=12x-x^2+48-4x

Simplify

20x=8x+48

20x-8x=48

12x=48

x=4

Find out the length of segment DB

DB=DH+HB

DB=(x+4)+(12-x)=16\ units

<em>Note</em> In this problem it was not necessary to determine the value of x to calculate the DB segment.

Anyway, the calculation was done for didactic purposes.

7 0
3 years ago
Read 2 more answers
I need help pleaseee ​
Free_Kalibri [48]
7(p+10)+9=5(p-2)-7p
7p+79=-2p-10
9p=-89
p=-9.89
8 0
3 years ago
an average person has 6x10 2power times as many red blood cells as white blood cells. A small sample of blood has 7x10 3power wh
dexar [7]

Answer:

4.2×10to the 6th or 4,200,000

Step-by-step explanation:

First you have to know that you are multiplying these two numbers. When you multiply exponents like there you add the matissa's (6&7) and add the exponents.

6×10to the 2 * 7×10to the 3rd

42 × 10to the 2+3

42×10to the 5th

Something else you need to know is your matissa cant be higher than 10

So:

4.2 × 10to the 6th is your answer

7 0
4 years ago
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