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3 years ago

HELPPP!! WILL GIVE BRAINLIEST!!!Given the function f(x) = 8x^2-4x+7. Calculate the following values:

Mathematics

1 answer:

DaniilM [7]3 years ago

8 0

Answer:

1: 47

2: 19

3: 7

4: 11

5: 31

Step-by-step explanation:

input the number next to F where x is. example: f(-2)= 8(-2)^2-4(-2)+7 and then solve using PEMDAS giving f(-2)=47 and so on.

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Write the equation of the line perpendicular to y=2/3 x−12 that passes through the point (4, -1) in slope-intercept form.

xenn [34]

Answer:

Step-by-step explanation:

perp. -3/2

y + 1 = -3/2(x - 4)

y + 1 = -3/2x + 6

y = -3/2x + 5

7 0

3 years ago

5/8 +1/2 in lowest terms

Rufina [12.5K]

Answer:

9/8 or 1 1/8

Step-by-step explanation:

5/8 +1/2

5/8+ 4/8 = 9/8 or 1 1/8

4 0

3 years ago

Please help me asap!!!!! Worth 20 points

jeka57 [31]

Answer:

Step-by-step explanation

Third, second, first.

The third has 5% chance that it will get the investor its money back, second having a 34% of the investor getting its money back, and the first having a 54% chance. Hope this was quick enough for you!

8 0

1 year ago

Read 2 more answers

for the data values below construct a 95 confidence interval if the sample mean is known to be 12898 and the standard deviation

Volgvan

Answer:

A 95% confidence interval for the population mean is [3315.13, 22480.87] .

Step-by-step explanation:

We are given that for quality control purposes, we collect a sample of 200 items and find 24 defective items.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample proportion of defective items = 12,898

s = sample standard deviation = 7,719

n = sample size = 5

$\mu$ = population mean

Here for constructing a 95% confidence interval we have used a One-sample t-test statistics as we don't know about population standard deviation.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-2.776 < $t_4$ < 2.776) = 0.95 {As the critical value of t at 4 degrees of

freedom are -2.776 & 2.776 with P = 2.5%}

P(-2.776 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.776) = 0.95

P( $-2.776 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.776 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-2.776 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.776 \times {\frac{s}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X-2.776 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+2.776 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $12,898-2.776 \times {\frac{7,719}{\sqrt{5} } }$ , $12,898+2.776 \times {\frac{7,719}{\sqrt{5} } }$ ]

= [3315.13, 22480.87]

Therefore, a 95% confidence interval for the population mean is [3315.13, 22480.87] .

5 0

3 years ago

What is 0.6 multiplied by 0.5

liberstina [14]

Answer:

0.3

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers