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2 years ago

HELPPP!! WILL GIVE BRAINLIEST!!!Given the function f(x) = 8x^2-4x+7. Calculate the following values:

Mathematics

1 answer:

DaniilM [7]2 years ago

8 0

Answer:

1: 47

2: 19

3: 7

4: 11

5: 31

Step-by-step explanation:

input the number next to F where x is. example: f(-2)= 8(-2)^2-4(-2)+7 and then solve using PEMDAS giving f(-2)=47 and so on.

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if mn is a midsegment to abc find the values of x and y. this is the only time im gonna use this so here's 50 points

Sliva [168]

X would equal 3 and y would equal 7

thanks for the points to mate

7 0

2 years ago

The focal lengths of the objective lens and the eyepiece of a microscope are 0.50 cm and 2.0 cm, respectively, and their separat

VladimirAG [237]

Answer:

- 103.7

Step-by-step explanation:

Given:

Focal length of the eyepiece, f = 2.0 cm

Focal length of the objective lens, f' = 0.50 cm

Separation for minimum eyestrain = 6,0 cm

Image distance, v = - 25 cm

Now, from the lens formula,

$\frac{1}{f}=\frac{1}{u}+\frac{1}{v}$

here, u is the object distance

on substituting the respective values, we get

$\frac{1}{2}=\frac{1}{u}+\frac{1}{-25}$

u = 1.852 cm

also, the separation is adjusted for minimum eyestrain,

therefore, image distance for the objective lens, v' = 6 - 1.852 = 4.148 cm

Now, for the objective lens

using the lens formula, we get

$\frac{1}{0.5}=\frac{1}{u'}+\frac{1}{4.418}$

Here, u' is the distance between the physical object and objective lens

u' = 0.568 cm

Thus,

Magnification, m = $-\frac{vv'}{ff'}$

m = $-\frac{25\times4.418}{0.5\times2}$

m = - 103.7

4 0

2 years ago

What is the area of cross-section ADGF of this right rectangular prism?

dedylja [7]

Answer:

C.52 square units

Step-by-step explanation:

We are given that

Length of cross-section ADGF,l=13units

Length of cross-section ADGF, b=4 units

We have to find the area of cross-section ADGF of this right rectangular prism.

We know that

Area of rectangle= $l\times b$

Using the formula

Area of cross-section ADGF of this right rectangular prism

= $13\times 4$

Area of cross-section ADGF of this right rectangular prism=52square units

Option C is correct.

C.52 square units

5 0

2 years ago

A circular cylindrical container, open at the top, and having a capacity of 24pi cubic inches, is to be manufactured. If the cos

otez555 [7]

Answer: radius r = 2 inches

height h = 6 inches

Step-by-step explanation:

Given;

Volume V = 24πin3

Volume of a cylinder is given by

V = πr^2h

h = V/πr^2. ....1

Where, h = height and r = radius of cylinder

For the surface area of the cylinder with open top. we have,

S = 2πrh + πr^2

For the cost of materials used, let k represent the cost of materials used for the body of the cylinder.

Then, for the bottom will be 3k

Total cost will be represented by C, which gives

C = 2πrhk + 3πr^2k. .....2

Substituting eqn 1 to 2, we have;

C = 2πrVk/πr^2 + 3πr^2k

C = 2Vk/r + 3πr^2k

The material cost is minimum at dC/dr = 0

dC/dr = -2Vk/r^2 + 6πrk =0

6πrk = 2Vk/r^2

r^3 = 2V/6π

r = (2×24π/6π)^-3

r = (8)^-3

r = 2

Substituting r = 2 into eqn1

h = 24π/π(2^2)

h = 24/4 = 6

h = 6

5 0

2 years ago

What is the value of the expression (-8/9) + (-2/3) x (-4 1/2)

geniusboy [140]

$\frac{4}{9}$

I hope this this is what you need ..

6 0

2 years ago