The answer to the question is 30.
Answer:
Step-by-step explanation:
A discrete variable is one which can be counted or which can be associted with the set of natural numbers.
A continuous variable is one which cannot be counted.
a. of unbroken eggs in a randomly chosenstandard egg carton
--Discrete
b. of students on a class list for a particular course who are absent on the first day of classes
----Discrete
c. of times a duffer has to swing at a golfball before hitting it
----Discrete
d. of a randomly selected rattlesnake
--Continuous
e. of royalties earned from the sale of a firstedition of 10,000 textbooks
--Continuous
f. of a randomly chosen soil sample
--Continuous
g. (psi) at which a randomly selected tennisracket has been strung
--Continuous
h. number of coin tosses required for threeindividuals to obtain a match (HHH or TTT)
---Discrete
The evaluation of the expression, if m = − 4 , n = 1 , p = 2 , q = − 6 , r = 5 , and t = − 2 | 16 + 4 ( 3 q + p ) is 46.
<h3>How can the expression be simplified?</h3>
the given expression is t = − 2 | 16 + 4 ( 3 q + p )
Then since we are given m = − 4 , n = 1 , p = 2 , q = − 6 , r = 5
Then, we can substitute all the given values of the terms into the given expression as :
t = − 2 | 16 + 4 ( 3 q + p )
t= -2 I 16+4(-18+2)
t= -2 I 16+4(-16)
t= -2 I 16 -64
t= -2 I -48
t =46
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The least and highest value of the house before being rounded are £184999 and £175000 respectively.
The initial value of Sue's house before the increase is £205,000
£180,000 correct to 2 significant figures :
The greatest value of the house would be a sum in which the third significant figure is a value less than 5 and the succeeding values are highest
The least value of house would be a sum in which the third significant value is 5 and the succeeding values are lowest.
2.)
Let the price before the increase = p
- Price after increase = £219350
7% of p = 219350
(1+7%) × p = 219350
1.07p = 219350
p = 219350 / 1.07
p = £205,000
Therefore, the price of the house before the increase is p = £205,000
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