When is the substitution method a better method than graphing for solving a system of linear equations?

What is 49/25 in a decimal

PSYCHO15rus [73]

49/25 converted into decimal form is
1.96
Hope this helps!

3 0

3 years ago

Read 2 more answers

Part A picture above

-BARSIC- [3]

Answer:

Part A C = (10,5) Part B C. D'(0,10)

Step-by-step explanation:

Part A

Since c is at the point (2,1) in relation to the origin, we can multiply those distances by our scale factor of 5

(2,1) * 5 = (10,5)

The new point C is going to be (10,5)

Part B

If you dilate with a factor of 5 -- relative to the origin -- you have to multiply the distance from the origin by 5.

In this case, point D is already on the y axis, so it's x value wouldn't be affected. Point D is currently 2 units away from (0,0), so we can multiply 2*5 to get 10 -- our ending point is (0,10)

8 0

3 years ago

Parallelograms are four sided figures that have two pairs of opposite, parallel sides. Quadrilateral ABCD

otez555 [7]

Answer:

(A) It would have to lie on AB because DC would rotate halfway around M. B would lie on D and A would lie on C.

(B) AD would lie on the BC line. D would lie on B and A would lie on C.

(C) The Lines CD and AD would only intersect if one line had to rotate 180 degrees around M.

8 0

2 years ago

Rory earned an 84% on his test. He answered 21 questions correctly. How many total questions were on the

Anna35 [415]

Answer:

21 is 84% to 25, so there would be 25 total questions on the test

4 0

3 years ago

A true/false test has 40 questions. Suppose a passing grade is 30 or more correct answers. Test the claim that a student knows m

Angelina_Jolie [31]

Answer:

z≈3.16

p≈0.001

we reject the null hypothesis and conclude that the student knows more than half of the answers and is not just guessing in 0.05 significance level.

Step-by-step explanation:

As a result of step 2, we can assume normal distribution for the null hypothesis

step 3:

z statistic is computed as follows:

z= $\frac{X-M}{\frac{\sqrt{p*(1-p)} }{\sqrt{N} } }$ where

X is the proportion of correct answers in the test ( $\frac{30}{40}$ )
M is the expected proportion of correct answers according to the null hypothesis (0.5)

p is the probability of correct answer (0.5)
N is the total number of questions in the test (40)

z= $\frac{0.75-0.50}{\frac{\sqrt{0.5*(0.5)} }{\sqrt{40} } }$ ≈ 3.16

And corresponding p value for the z-statistic is p≈0.001.

Since p<0.05, we reject the null hypothesis and conclude that the student knows more than half of the answers and is not just guessing in 0.05 significance level.

7 0

3 years ago