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Setler [38]
2 years ago
10

HELP WILL GIVE BRAINLIEST

Mathematics
1 answer:
mina [271]2 years ago
6 0

Answer:

38° po siya

HOPE IT HELPS

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svlad2 [7]
I have NO idea. Try searching on the enternet

4 0
3 years ago
5<br> 0 = - in<br> =<br> in quadrant II<br> Given cos =<br> Find sin<br> 3
____ [38]

Answer:

sinΘ = \frac{2}{3}

Step-by-step explanation:

using the identity

sin²x + cos²x = 1  ( subtract cos²x from both sides )

sin²x = 1 - cos²x ( take square root of both sides )

sinx = ± \sqrt{1-cos^2x}

given

cosΘ = - \frac{\sqrt{5} }{3} , then

sinΘ = ± \sqrt{1-(-\frac{\sqrt{5} }{3})^2 }

        = ± \sqrt{1-\frac{5}{9} }

        = ± \sqrt{\frac{4}{9} }

        = ± \frac{2}{3}

since Θ is in quadrant II where sinΘ > 0 , then

sinΘ = \frac{2}{3}

7 0
2 years ago
Which values are solutions to x&lt;16?
leonid [27]

Answer:

Option D.

x can take values from 15downwards. It can't be 16 because the expression clearly states that x is less than 16. So x can take value from any number below 16.

8 0
2 years ago
Answer B Im confused
Finger [1]

Answer:

120 degrees

Step-by-step explanation:

interior angle of regular polygon = [ ( n − 2 ) × 180 ] / n

n = number of sides

hence, in b), n = 6

interior angle of regular polygon = [ ( 6 − 2 ) × 180 ] / 6 = 120

6 0
2 years ago
Read 2 more answers
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