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SVEN [57.7K]
3 years ago
6

Determine the remainder when (x3 – 5x2 14x – 5) is divided by (x 3)

Mathematics
2 answers:
kogti [31]3 years ago
8 0

Answer:

The remainder is -119

Step-by-step explanation:

(x^3 - 5x^2+ 14x - 5) divide by (x+3)

we use the remainder theorem to find the remainder

We are given with x+3

x+3=0, x=-3

To find remainder, we substitute -3 for x

(x^3 - 5x^2+ 14x - 5)

((-3)^3 - 5(-3)^2+ 14(-3) - 5)

-27-45-42-5=-119

The remainder is -119

Bogdan [553]3 years ago
6 0
Hello,

P(x)=x^3-5x^2+14x-5

P(-3)=(-3)^3-5*(-3)²+14*(-3)-5=-119
Remainder=-119
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