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SVEN [57.7K]
3 years ago
6

Determine the remainder when (x3 – 5x2 14x – 5) is divided by (x 3)

Mathematics
2 answers:
kogti [31]3 years ago
8 0

Answer:

The remainder is -119

Step-by-step explanation:

(x^3 - 5x^2+ 14x - 5) divide by (x+3)

we use the remainder theorem to find the remainder

We are given with x+3

x+3=0, x=-3

To find remainder, we substitute -3 for x

(x^3 - 5x^2+ 14x - 5)

((-3)^3 - 5(-3)^2+ 14(-3) - 5)

-27-45-42-5=-119

The remainder is -119

Bogdan [553]3 years ago
6 0
Hello,

P(x)=x^3-5x^2+14x-5

P(-3)=(-3)^3-5*(-3)²+14*(-3)-5=-119
Remainder=-119
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The lowest common multiple of 10, 15 and p is 150. Find the two possible values of p which are odd numbers.
natka813 [3]

Answer:

p = 3, p = 5

Step-by-step explanation:

Express 150 as a product of prime factors, that is

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Write the ratio as a fraction in simplest form, with whole numbers in the numerator and denominator.
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△BCD ​ is a right triangle. The length of the hypotenuse is 18 centimeters. The length of one of the legs is 14 centimeters. Wha
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Answer:

The answer to your question is   b = 11.31 cm  or   8\sqrt{2} cm

Step-by-step explanation:

Data

hypotenuse = 18 cm

one leg = 14 cm

second leg = ?

Process

1.- Use the Pythagorean Theorem to solve this problem

                 c² = a² + b²

c = hypotenuse

a = longer leg

b= shorter leg

2.- Substitution

                        18² = 14² + b²

-Solve for b

                         b² = 18² - 14²

-Simplify

                         b² = 324 - 196

                         b² = 128

-Find the prime factors of 128

                          128   2

                            64  2

                             32  2

                             16  2

                              8  2

                              4  2

                              2  2

                               1

          128 = 2⁶2¹                                    

-Result

                         b = 11.31   or   8\sqrt{2}

5 0
2 years ago
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