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PIT_PIT [208]
3 years ago
13

I neeeeeeeeeeeeeeeeeeeeeeeeeeeeed heeeeeeeeeeeeeeeeeeeelppp

Mathematics
1 answer:
zepelin [54]3 years ago
8 0

Answer:

35 i<em>s answer please tell me if i am right </em>

Step-by-step explanation:

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X+y+3z=-16<br>x+y+7z=-32<br>x-8y-6z=11
GaryK [48]

x+y+3z=-16 ... (1)

x+y+7z=-32 ...(2)

x-8y-6z=11 ... (3)

Let's subtract equation (1) and (2) so that we can eliminate x and y. So,

x+y+3z=-16

x+y+7z=-32

____________________

(x-x)+(y-y)+(3z-7z)=(-16)-(-32)

0+0-4z=-16+32

-4z= +16

\frac{-4z}{-4} =\frac{16}{-4} Dividing each sides by -4.

z=-4

Now plug in z=-4 in equation (2) and (3). So, by plug in -4 for z in equation (2) we will get

x+y+7(-4)=-32

x+y-28=-32

x+y=-32+28

x+y=-4 ....(equation (4)

Now let's plug into equation (3). So,

x-8y-6(-4)=11

x-8y+24=11

x-8y=11-24

x-8y=-13 ......... equation(5)

Now we have two equations (4) and (5) with two variables x and y which we can solve now.

We can eliminate y from equation (4) and (5) by making equal and opposite coefficient of y's. So, multiply equation (4) by 8.

(x+y=-4)x8

8x+8y=-32....... (6)

Now after adding equation (5) and (6) wewill get,

9x=-45

9x/9=-45/9

x=-5

Now we can plug in x=-5 and z=-4 in any equation to get the value of y. So, let's plug in to equation (1).

-5+y+3(-4)=-16

-5+y-12=-16

y-17=-16

y=17-16

y=1

So, x=-5, y=1 and z=-4

4 0
3 years ago
Read 2 more answers
Can someone answer this question plz
Murljashka [212]

Ahh, finally a calculus question :D

When you are deriving two functions that are multiplied by each other, you need to use the product rule. I'll rewrite the definition here:

\frac{d}{dx}(f(x)g(x)) =

f(x)(\frac{d}{dx}g(x)) + g(x)( \frac{d}{dx}f(x))

(I would just write f prime and g prime but there is no coma in the equation tool on this app. This is a better version:)

(d/dx) f(x)g(x) = f(x)g'(x) + f '(x)g(x)

So you have e^x and cos(x) multiplied together and you need to derive the whole function?

The first part of the derivative is the first function times the derivative of the second. Im going to pick cos(x) as my first function and e^x as the second one but it really doesn't matter which one you chose first.

With that being said, the first part looks like this:

\cos(x) {e}^{x} +

(Remember that the derivative of e^x is e^x)

Now, we just have to add the second function times the derivative of the first function, which in this case equals negative sin times e^x

\cos(x) {e}^{x}  - sin(x) {e}^{x}

(Rememebr that the derivative of cos(x) is equal to -sin(x)

And that is your derivative ;)

3 0
3 years ago
Question 2 of 6
matrenka [14]

Answer:

it's -1

Step-by-step explanation:

\frac{(-2)(-3)+2(-6)}{-(3)(-6)}\\ \\\frac{-6 + (-12)}{18}\\ \\\frac{-18}{18}=-1

7 0
2 years ago
Read 2 more answers
Help me please. Help I’m stuck
Crank
Sin(B=3/5
cos(B=4/5

The answer is false
5 0
4 years ago
Read 2 more answers
Listen
disa [49]

Answer:

A 29 is the answer to the problem

5 0
3 years ago
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