3 years ago

Im having a hard time on edge any tips?

Mathematics

2 answers:

bixtya [17]3 years ago

7 0

Answer:

just search up the answers on googl or here mostly it will have them all

Step-by-step explanation:

slamgirl [31]3 years ago

5 0

Answer:

Take deep breaths and focus, don't be afraid to ask for help.

Good luck!

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Firlakuza [10]

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2 years ago

If y=7.2 and r= 1.1 have been rounded to 1 decimal place find the possible value of y x r

Shkiper50 [21]

Answer:

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3 years ago

Can you solve -3(y-5)=24

garri49 [273]

Answer:y=-3

Step-by-step explanation:yes firs multiply everything by -3 in parenthesies

Then you would subtract 15 from both sides

Next you would divide 9 by -3 and you would get -3

So y =-3

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4 years ago

Read 2 more answers

Answer the following questions. Leave in simplest terms.

matrenka [14]

Area = length x width
Area = (5x + 1)*(3x - 2)
Area = 5x*3x + 5x*-2 + 1*3x + 1*-2
Area = 15x^2 - 10x + 3x - 2
Area = 15x^2 - 7x - 2 :)

5 0

3 years ago

1.Solve the differential equation dy/dx= y^2/x^3 for y=f(x) with the condition y(1) = 1.

Elza [17]

This ODE is separable, so you can write

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{y^2}{x^3}\iff\dfrac{\mathrm dy}{y^2}=\dfrac{\mathrm dx}{x^3}$

Integrating both sides gives

$-\dfrac1y=-\dfrac1{2x^2}+C$

and given the initial condition $y(1)=1$ , you have

$-\dfrac11=-\dfrac1{2(1)^2}+C\implies C=-\dfrac12$

so that the solution is

$-\dfrac1y=-\dfrac1{2x^2}-\dfrac12\implies y=\dfrac1{\frac1{2x^2}+\frac12}=\dfrac{2x^2}{1+x^2}$

4 0

3 years ago