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2 years ago

Im having a hard time on edge any tips?

Mathematics

2 answers:

bixtya [17]2 years ago

7 0

Answer:

just search up the answers on googl or here mostly it will have them all

Step-by-step explanation:

slamgirl [31]2 years ago

5 0

Answer:

Take deep breaths and focus, don't be afraid to ask for help.

Good luck!

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Lin runs 5 miles in 40 minutes.

natima [27]

8 mins
1 mile
1 hr and 12 mins

3 0

2 years ago

NEED HELP ASAP PLEASE

AnnZ [28]

Answer:

8.5%

Step-by-step explanation:

I=PRT

85= 2000*r*0.5

85=1000r

0.085=r

8.5%

6 0

2 years ago

Which choice correctly shows rounding to the hundredths place?

Romashka-Z-Leto [24]

Choice A is false because they are rounding to the nearest tenth (one decimal place) and not nearest hundredth (two decimal places)

Choice B is false as well because 3.825 should round to 3.83. The 5 at the end tells you to round up.

Choice C is false too. The value 3.824 should round to 3.82. Not sure how they got 3.81, so it seems like a deliberate trick question or silly answer.

Choice D is true. The three decimal values are rounded properly to the correct number of decimal places.

Therefore choice D is the answer

4 0

2 years ago

Read 2 more answers

In 31 days, Gwen's dog sleeps 496 jours.If she sleeps that same number of hours each night, how many hours does she sleep per ni

g100num [7]

It 496 ÷ 31 = 16 days

4 0

2 years ago

Read 2 more answers

the first group of students consists of 10 and their average age was 13 years old the next group consisted of 30 students and th

Kazeer [188]

Answer: The average was 9 years old find the average age of both groups is 10 years old.

Step-by-step explanation:

Formula foe average : $\text{Average} =\dfrac{\text{Sum of all observations}}{\text{Number of observations}}$

Given : The first group of students consists of 10 and their average age was 13 years old.

i.e. $13=\dfrac{\text{Sum of ages of students of first group}}{10}\\\\\Rightarrow\ \text{Sum of ages of students of first group}=13\times10=130$ (1)

The next group consisted of 30 students and their average was 9 years old.

i.e. $9=\dfrac{\text{Sum of ages of students of next group}}{30}\\\\\Rightarrow\ \text{Sum of ages of students of nextgroup}=9\times30=270$ (2)

Then from (1) and (2) , the sum of both groups (first group and next group )students = 130+270 =400

Combined students of both groups (first and next group )= 10+30=40

Now , the average of both groups = $\dfrac{\text{Sum of combined students}}{\text{combined students}}$

$=\dfrac{400}{40}=10$

Hence, the average was 9 years old find the average age of both groups is 10 years old.

4 0

3 years ago