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3 years ago

8. If the speed of a wave is 1500 m/s and its frequency is 200 Hz, what is the wavelength?

Physics

1 answer:

sammy [17]3 years ago

4 0

formula for wavelength = speed/frequency

So 1500/200 = 7.5 meters

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4 years ago

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3 years ago

3. Calculate the wavelength of wave that has a frequency of 4.75 x 1012Hz.

Klio2033 [76]

Frequency=v=4.75×10^12Hz
Wavelength=?

We know

$\boxed{\sf \lambda=\dfrac{C}{V}}$

$\\ \sf\longmapsto \lambda=\dfrac{3\times 10^8ms^{-1}}{4.75\times 10^{12}s^{-1}}$

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3 years ago

Explain newton 2nd law ???<br><br>

shusha [124]

Explanation:

Newton's second law simply says that the net force on an object is equal to the object's mass times its acceleration.

∑F = ma

For example, think of a game of tug-of-war, in which two teams pull on a rope in opposite directions.

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4 years ago

Given a double slit apparatus with slit distance 2 mm, what is the theoretical maximum number of bright spots that I would see w

katen-ka-za [31]

Answer:

The values is $m_{max} = 8001 \ bright \ spots$

Explanation:

From the question we are told that

The slit distance is $d = 2 \ mm = 2*10^{-3} \ m$

The wavelength is $\lambda = 500 \ nm = 500 *10^{-9} \ m$

At the first half of the screen from the central maxima

The number of bright spot according to the condition for constructive interference is

$n = \frac{d * sin (\theta )}{\lambda}$

For maximum number of spot $\theta = 90^o$

$n = \frac{2*10^{-3} * sin (90 )}{500 *10^{-9}}$

$n =4000$

Now for the both sides plus the central maxima we have

$m_{max} = 2 * n + 1$

substituting values

$m_{max} = 2 * 4000 + 1$

$m_{max} = 8001 \ bright \ spots$

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4 years ago